Can I use string.Join (or an alternative) in .NET 3.x?

Question

I posted a question over here: Selecting a substring from a string in C# and I got a nice suggestion of using following code:

int index = String2.IndexOf(String1);
if(index >= 0)
{
    string result = String1;
    if (String1.Length < String2.Length)
    {
        string rest = String2.Substring(index + String1.Length);
        var chars = rest.TakeWhile(c => !Char.IsLetter(c) && !Char.IsWhiteSpace(c));
        result = result + string.Join("", chars);
    }
}

I used it in .Net 4.0 and it's working fine. The problem is that I have to use .Net 3.0. Is there any way I can use String.Join in .NET 3.0 or .NET 3.5?

Are you sure? System.Join exist since .NET Framework 2.0 as far as I know. What is the values of String2 and String1? What is your output and what do you expect? — Soner Gönül
– Soner Gönül, Commented Mar 5, 2014 at 14:14
.Net 3.0? I never heard anyone use that. .Net 3.5 is more common, but that will have what you need. If you are missing Linq features take a look at LinqBridge or similar frameworks — DaveShaw
– DaveShaw, Commented Mar 5, 2014 at 14:20
@SonerGönül link in this they described that String.join does not exist in Dot Net 3.5 — Kamran
– Kamran, Commented Mar 5, 2014 at 14:30

Tim Schmelter · Accepted Answer · 2014-03-05 14:30:01Z

1

In .NET 3 there are only two overloads for String.Join, so you need strings and you don't have LINQ.

Another way is not to use String.Join at all but for example a StringBuilder:

StringBuilder sb = new StringBuilder();
for (int i = 0; i < rest.Length; i++)
{
    char c = rest[i];                       
    bool takeChar = !Char.IsLetter(c) && !Char.IsWhiteSpace(c);
    if (takeChar)
        sb.Append(c);
    else
        break;
}
result = result + sb.ToString();

edited Mar 5, 2014 at 14:30

answered Mar 5, 2014 at 14:17

Tim Schmelter

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3 Comments

Dirk Over a year ago

Wouldn't that call the String.Join(string, params object[]) one which was introduced in 4.0 too?

StyxRiver Over a year ago

Similar functionality, but not exact. The call resulting above goes to String.Join(string, string[]) because of the Select LINQ statement returns string values. The 4.0 call with params does not require a strongly-typed string array, and can take a comma-separated list of objects.

Tim Schmelter Over a year ago

@Dirk: i have edited my answer to use a StringBuilder since LINQ in .NET 3 is also a problem.

Oscar Bralo · Accepted Answer · 2014-03-05 14:18:03Z

0

I don´t know. I will give you a way to do it.

Convert your string in a StringBuilder in the System.Text namespace

Then do something like:

StringBuilder sb = new StringBuilder();
sb.Append(chars);

And pass your chars.

The result will be the same

answered Mar 5, 2014 at 14:18

Oscar Bralo

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Comments

Dirk · Accepted Answer · 2014-03-05 14:18:13Z

0

String.Join does work in .NET versions prior to 4.0 with the exception of the overloads taking an IEnumerable<T> and IEnumerable<string>.

In your code chars is an IEnumerable<char> so the method you use will be unavailable. You can use a different overload, for example

String.Join("", chars.Select(c => c.ToString()).ToArray());

which will use the String.Join(string, string[]) one.

answered Mar 5, 2014 at 14:18

Dirk

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