Passing parameters to objects whilst simultaneously instantiating an array

Question

I have an array of Object and wondered if I could pass parameters whilst simultaneously instantiating the array.

For example:

theArray = new Object(20, 20, 20)[30];

I want to avoid looping through each element and passing parameters to them after the array has been created if I can help it.

I know the above syntax isn't correct, but it illustrates what I'm trying to achieve.

Thanks for your responses!

No, you can't. But look at the Arrays class for alternatives. — Sotirios Delimanolis
– Sotirios Delimanolis, Commented Mar 5, 2014 at 16:08
You might be able to dosomething like theArray = {new Object(20, 20, 20), new Object(20, 20, 20)...} but would still have to type them all out. Not entirely sure this would work, but worth a shot. — dev
– dev, Commented Mar 5, 2014 at 16:08

Rainbolt · Accepted Answer · 2014-03-05 16:15:55Z

2

Use Arrays.fill() to avoid looping.

Example

Create an array with 30 instances of MyClass that all have the values 20, 20, 20.

MyClass[] theArray = new MyClass[30];
Arrays.fill(theArray, new MyClass(20,20,20));

edited Mar 5, 2014 at 16:15

answered Mar 5, 2014 at 16:10

Rainbolt

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4 Comments

Bob Stout Over a year ago

Nice...didn't know about that. Can't think of a use for it for what I'm doing, but it's good to know if the need arises.

Rainbolt Over a year ago

@BobStout You can't think of a use for an array of 30 identical objects? You aren't very imaginative.

Bob Stout Over a year ago

I mainly deal with thousands of objects, all different, all interrelated. My imagination is currently occupied. :)

Bradley Over a year ago

This is almost what I'm looking for. I guess it's a lack in my understanding of the task at hand. This will provide all the objects in the array with the same properties. However I need them all to have the same properties, with a few exceptions. So I guess I will have to loop!

Salah · Accepted Answer · 2014-03-05 16:09:33Z

0

You could do something like this:

theArray = {20, 20, 20};

This means that you have an array with size of 3.

answered Mar 5, 2014 at 16:09

Salah

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Comments

Bob Stout · Accepted Answer · 2014-03-05 16:14:45Z

-1

If you're just trying to keep your main code clean, shuffle it off to a function:

theArray = getObjects(30);
...
private Object[] getObjects(int numObjects){
    Object[] returnObjects = new Object[30];
    for(int x=0; x<numObjects;x++){
    //etc, etc, etc
    }
    return returnObjects;
}

answered Mar 5, 2014 at 16:14

Bob Stout

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3 Comments

Bradley Over a year ago

It's more about performance, I don't want to have to loop through each element in the array and pass parameters to them if I can just do that at the point where I instantiate the array.

Bob Stout Over a year ago

John's answer is best for you then. Check out odys's answer at stackoverflow.com/questions/9128737/…

Bob Stout Over a year ago

If you're going to downvote the answer, at least be a man and explain why.

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