XPath: How to select a range of nodes in the node set?

Question

I want to select a range of nodes in a node set. I tried, but I cannot get the result.

example.xml:

<div>
    <p class="p1">a</p>
    <p class="p2">b</p>
    <p class="p3">c</p>
</div>
<div>
    <p class="p1">aa</p>
    <p class="p2">bb</p>
    <p class="p3">cc</p>
</div>
<div>
    <p class="p1">aaa</p>
    <p class="p2">bbb</p>
    <p class="p3">ccc</p>
</div>
<div>
    <p class="p1">aaaa</p>
    <p class="p2">bbbb</p>
    <p class="p3">cccc</p>
</div>

I want to get the second to third pnodes( have class="p1"), I wrote the xpath:
"//div/p[@class='p1'][position()>=2 and position()<4]", But it failed.I guess that if every time "//div/p[@class='p1']" get one node, and its position is 0, so I can not get a node which position>=2 and position<4, so the result is none.But How can I write the xpath?

Community · Accepted Answer · 2017-05-23 12:10:56Z

9

Your guess is about correct.

The ([]) has a higher precedence (priority) than (// and /). [For Reference]

So you need to wrap XPath before position filter within brackets as follow :

(//div/p[@class='p1'])[position()>=2 and position()<4]

edited May 23, 2017 at 12:10

CommunityBot

11 silver badge

answered Mar 6, 2014 at 3:29

har07

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