Putting array_filter() in a function

Question

I would like to transform the code below in a function

function filter($row){return ($row['id_menu'] == 10);}

$matches = array_filter($array_mostrar_privilegios, "filter");
foreach ($matches as $element)
{
    echo $element['consultar'];
}

like

function filter($row, $num)
{
    return ($row['id_menu'] == $num);
}
function find($my_array, $num)
{
    $matches = array_filter($my_array, "filter($row, $num)");
    foreach ($matches as $element)
    {
        return $element['consultar'];
    }
}

but i don't how to make it work

filter doesn't call find, and find doesn't call filter. I don't understand what you're trying to achieve. — ʰᵈˑ
– ʰᵈˑ, Commented Mar 6, 2014 at 17:30
@hd.: The 2nd parameter to array_filter is a callback. He wants to call filter with an extra parameter. — gen_Eric
– gen_Eric, Commented Mar 6, 2014 at 17:31

gen_Eric · Accepted Answer · 2014-03-06 18:00:21Z

2

If you have PHP 5.3+, then there is no need to use a string as the callback parameter. PHP 5.3+ has anonymous functions.

$matches = array_filter($my_array, function($row) use($num){
    return filter($row, $num);
});

If you do not have PHP 5.3, then you can use create_function (warning: this uses eval()):

$matches = array_filter($my_array, create_function('$row', 'return filter($row,'.$num.');'));

edited Mar 6, 2014 at 18:00

answered Mar 6, 2014 at 17:30

gen_Eric

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5 Comments

Guhh Over a year ago

it returns the follow error: "Parse error: syntax error, unexpected T_FUNCTION"

gen_Eric Over a year ago

That means you have PHP 5.2 or below.

Amal Over a year ago

@user3249927: Your options are (in the order of preference): 1) Upgrade to a more recent PHP version, 2) Define the function outside (as you're currently doing), 3) Use create_function().

gen_Eric Over a year ago

@user3249927: Try the 2nd example I've added to the answer. I would consider upgrading PHP, but if you can't then create_function should work.

Guhh Over a year ago

I'will try to update later and try your first option before. Thanks for the advice

Mark Baker · Accepted Answer · 2014-03-06 17:30:30Z

2

Using closures:

function find($my_array, $num)
{
    $matches = array_filter(
        $my_array, 
        function filter($row) use($num) {
            return ($row['id_menu'] == $num);
        }
    );
    foreach ($matches as $element)
    {
        return $element['consultar'];
    }
}

except that your return inside the foreach will only return the first element from $matches

If you expect multiple $matches values, and want to return them all, consider using yield to turn this into a generator

answered Mar 6, 2014 at 17:30

Mark Baker

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3 Comments

Guhh Over a year ago

i had to remove the "filter" to work.. and it return a error to me "Parse error: syntax error, unexpected T_FUNCTION"

Amal Over a year ago

@user3249927: If you only need the first result, why do you need a loop? Just print the first result: $matches[0]['consultar'].

Guhh Over a year ago

i really need like this, coz i have a lot of lines on this array. Thanks for helping

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