TypeError: 'int' object is not callable in list

Question

I was trying out a program for legendre's function as given below, but it showed some error. I'm not used to arrays in Python, but know them in C++.

from math import *

j = 0
arr = [0 for i  in range (6)]
k= 3.75
arr[0]= 1
arr[1] = 1 
x0= -1
xf = 1
x= x0
h= 0.1

f1 = open('leg.dat', 'w')

while x< xf:
    for j in range(0,5):
        arr[j+2]= (arr[j] *(j*j + j -k)/((j+2)*(j+1)))
        print >>f1, x,(x**j)*(((j+2)(j+1)*arr[j]) - (j*(j-1)*arr[j]) - (2*j*arr[j]) + k*arr[j])
        x = x+h

f1.close ()

error shown :

print>>f1, x,(x**j)*(((j+2)(j+1)*arr[j]) - (j*(j-1)*arr[j]) - (2*j*arr[j]) + k*arr[j])

TypeError: 'int' object is not callable

Wojciech Walczak · Accepted Answer · 2014-03-06 17:37:08Z

4

Here's the problem:

(j+2)(j+1)

Python is trying to call the j+2 with j+1 as argument.

>>> j = 1
>>> (j+2)(j+1)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'int' object is not callable

Did you mean (j+2)*(j+1)?

answered Mar 6, 2014 at 17:37

Wojciech Walczak

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2 Comments

abhih1 Over a year ago

oops! got it! the program i'm trying to write is of legendre's function upto 4 terms and draw its graph. but even when i corrected that, the data points are giving 0 for every value of x. can u pls suggest a correction?

Wojciech Walczak Over a year ago

After removing writing to a file (and printing to stdout instead) your code produces the following output on my machine: -1 5.75 -0.9 -6.975 -0.8 -11.7 -0.7 1.17548958333 Traceback (most recent call last): File "55pkt.py", line 16, in <module> arr[j+2]= (arr[j] (jj + j -k)/((j+2)*(j+1))) IndexError: list assignment index out of range Are you experiencing the same results?

Kevin · Accepted Answer · 2014-03-06 17:36:42Z

1

print >>f1, x,(x**j)*(((j+2)(j+1)*arr[j]) - (j*(j-1)*arr[j]) - (2*j*arr[j]) + k*arr[j])
                        ^^^  ^^^

You didn't specify an operation between these two values. Did you mean to multiply them?

print >>f1, x,(x**j)*(((j+2)*(j+1)*arr[j]) - (j*(j-1)*arr[j]) - (2*j*arr[j]) + k*arr[j])

answered Mar 6, 2014 at 17:36

Kevin

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