I want a method to return two vectors to the calling function. Here is what I tried:
static Vector<String>[] method()
{
Vector<String>[] toret = new Vector<String>[2]; // GETTING ERROR HERE
for(...)
{
toret[0].add(...);
toret[1].add(...);
}
return toret;
}
public static void main()
{
Vector<String>[] obtained = method();
}
Need help to remove that error.
Don't try to create arrays of generics. Try returning a List<Vector<String>> instead.
static List<Vector<String>> method()
{
List<Vector<String>> toret = new ArrayList<Vector<String>>();
toRet.add(new Vector<String>());
toRet.add(new Vector<String>());
for(...)
{
toret.get(0).add(...);
toret.get(1).add(...);
}
return toret;
}
I'd also suggest using List<String> (and List<List<String>>) instead of Vector<String> (and List<Vector<String>>) unless you absolutely need elsewhere the method-level synchronization that Vector provides.
List<Vector<String>>? and what is advantage of using List<String> (and List<List<String>>) instead of Vector<String>?Vector is that you avoid the overhead of making synchronized calls when calling the various methods. ArrayList was introduced as an alternative to Vector primarily because it is more efficient in this way. When you do need synchronization, it is almost never at the single-method level anyway, so Vector buys you nothing but inefficiency.
You're doing 2 wrong things here:
Vector instead of ListYou can't create an array of concrete parameterized types. You have to go with a List<List<String>> rather.
instead of Vector[] toret = new Vector[2]; Use Vector toret = new Vector();
Also change like this
public static void main() { Vector obtained = method(); }
You can use 0 & 1 st index for your manipulations. Vector is a dynamic array. so if you want to ensure capacity just give Vector toret = new Vector(2)
Vector? stackoverflow.com/questions/1386275/…ArrayListinstead of an array.