SyntaxError {stack: (...), message: "Unexpected token <"}

Question

I have using ajax. Here creating json in PHP

$(document).ready(function(e) {
        var data='page=1';
        $('#loader_tracker').show();
        $.ajax({
        type: "GET",
        url: "getDetails.php",
        data:data,
        dataType:"json",
        success:function(data) {
            $('#loader_tracker').hide();
        },
         error:function(jqXHR, textStatus, errorThrown){
         console.log(errorThrown);
         console.log(textStatus);
         },
         complete: function(){
            $('#loader').hide();
        }

        });
        return false;

});

PHP COde

require_once('dbConnection.php');
$connection = new dbconnection();
$con = $connection->connectToDatabase();
header('Content-type: text/json'); 
die($response);

$vendorId = 2;
$name = "sample";
$latitude = 100;
$longitude = 200;

$device_details=array('devices' => array());

    for($i=1;$i<=20;$i++)
{

$details =array('id' => $vendorId, 'name' => $name, 'lat' => $latitude, 'lan' => $longitude);
array_push($device_details['devices'],$details);
}

echo json_encode($device_details);

It gives SyntaxError {stack: (...), message: "Unexpected token <"} Error

I cant find issue for this. I dont know how to add json format like this one[{devices:[{...}]}]

getDetails.php in this file check that there is no HTML on the top — Abhik Chakraborty
– Abhik Chakraborty, Commented Mar 19, 2014 at 6:46

xdazz · Accepted Answer · 2014-03-19 06:39:22Z

1

Remove the line below (which makes your response be invalid json):

print_r ("$device_details");

answered Mar 19, 2014 at 6:39

xdazz

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2 Comments

Mohaideen Over a year ago

I have add this line for testing.. Even i have remove this line, same error occur

Mohaideen Over a year ago

I dont know where it is. i think its json format error

Girish · Accepted Answer · 2014-03-19 06:47:37Z

0

Remove to debug code line print_r ("$device_details"); from PHP file, And use echo json response and terminate code.

header('Content-type: text/json'); 
die($response);

And also add header sometime create problem with content information so please add proper header information.

answered Mar 19, 2014 at 6:47

Girish

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1 Comment

Girish Over a year ago

@Mohaideen, can you add ajax response in question??

Robin C Samuel · Accepted Answer · 2014-03-19 06:53:38Z

0

Change the following code

print_r ("$device_details");
$response=json_encode($device_details);
print $response;

to,

echo json_encode($device_details);
die();

edited Mar 19, 2014 at 6:53

answered Mar 19, 2014 at 6:45

Robin C Samuel

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5 Comments

Mohaideen Over a year ago

Now i get this error SyntaxError {stack: (...), message: "Unexpected token ["}

Robin C Samuel Over a year ago

can you replace array_push($device_details['devices'],$details); to $device_details['devices'][] = $details;

Robin C Samuel Over a year ago

can you show the response string ? Or the result when you directly visit that page getDetails ? I thinks its json formating error

Mohaideen Over a year ago

I have modify my question. see above

Robin C Samuel Over a year ago

try $device_details=array(); for($i=1;$i<=20;$i++) { ... array_push($device_details,$details); }

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