How to split specific pattern using regex

Question

I have below string

Dim strTemplate as string = 
"<table>
  <tr>
       <td>Name</td>
       <td>Address</td>
       <td>City</td>   
  </tr>
  <tr>
       <td>[%Name%]</td>
       <td>[%Address%]</td>
       <td>[%City%]</td>   
  </tr>
</table>"

Dim strSplits = New List(Of String)(Regex.Split(strval, "REGEXRequired"))

Now i want to write regex with split above string and give only pattern string [%...%].

i.e. want [%Name%], [%Address%], [%City%] values in strSplits list.

any suggestion or help will be appreciated .

Tim Pietzcker · Accepted Answer · 2014-03-21 06:55:21Z

3

Why would you use Split() for that?

Dim strSplits = New List(Of String)(Regex.Matches(strval, "\[%.*?%\]"))

is much easier, isn't it?

answered Mar 21, 2014 at 6:55

Tim Pietzcker

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3 Comments

Prakash Patani Over a year ago

how can take distinct values ?

Tim Pietzcker Over a year ago

@PrakashPatani: What do you mean?

Prakash Patani Over a year ago

I mean matching value array contain distinct values. I had managed to do that..thanks for your help

aelor · Accepted Answer · 2014-03-21 06:55:05Z

1

this will get you going

/(\[%.*?%\])/g

demo here : http://regex101.com/r/kV2rK4

answered Mar 21, 2014 at 6:55

aelor

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