Why am I getting this error message "Warning: array_push() expects parameter 1 to be array, null given ..." When I removed the function and just run the for loop, it works, but not inside function. why?
<?php
$arr = array();
function callme() {
for ($x = 1; $x <= 10; $x++) {
array_push($arr, $x);
}
return $arr;
}
callme();
print_r($arr);
?>
Declare array $arr as global
$arr = array();
function callme() {
global $arr;
for ($x = 1; $x <= 10; $x++) {
array_push($arr, $x);
}
return $arr;
}
Or pass $arr as a parameter.
You need to do either of two things:
Add $array as function parameter and return that.
<?php
$arr = array();
function callme($array) {
for ($x = 1; $x <= 10; $x++) {
array_push($array, $x);
}
return $array;
}
$arr = callme($arr);
print_r($arr);
?>
If you don't like returns you can have the array as reference...
<?php
$arr = array();
function callme(&$array) {
for ($x = 1; $x <= 10; $x++) {
array_push($array, $x);
};
}
callme($arr);
print_r($arr);
?>
or define $arr als global in the function(least desired, you're stuck with only one array)
<?php
$arr = array();
function callme() {
global $arr;
for ($x = 1; $x <= 10; $x++) {
array_push($arr, $x);
}
return $arr;
}
callme();
print_r($arr);
?>
function callme() use(&$arr) {, though in this case that's not much better than global.
use is probably the closest to this.use, it' wouldn't necessarily be a global. Just in this special case it's basicially the same as using global. In other cases, say class methods for example, use has it's use. ;)Someone needs to learn some basics about variable scopes.
