Ruby 1.8.7
array = [[1.5,"cm"],[1.5,"cm"],[1.5,"m"]]
How to compare each array inside the variable array and see if it is equal, if equal then move on else if not equal then return the index of the array element which was not equal and stop comparing.
So in this example,
array[0] == array[1]
#=> true
Thus, move on
array[1] == array[2]
=> false
Hence return index i.e = 1
return 1
Here is how I would do using Array#each_index :
def compare_array_elements(array)
siz = array.size - 1
array.each_index { |i| return i if i != siz && array[i] != array[i+1] }
nil
end
array = [[1.5,"cm"],[1.5,"cm"],[1.5,"mm"]]
compare_array_elements(array) # => 1
array = [[1.5,"cm"],[1.5,"cm"],[1.5,"cm"]]
compare_array_elements(array) # => nil
siz you could just do array.each_index[0..-2]
array[0..-2].each_index BTW.. :)siz be before the comparison so that it short-circuits the && rather than comparing against a nil?[[1.5,"cm"],[1.5,"cm"],[1.5,"m"]]
.each_cons(2).with_index(1).find{|(a, b), i| a == b}.last
# => 1
