Regular expression to validate the user input

Question

I want a regular expression, which should start with alphabet or numbers and followed by alphanumeric character and in between, it may or may not contain forward or backward slash (\,/).

Highly appreciate your help.

Thanks :)

My reguler expression expecting / and \ as input. And i'm new to this reguler expression. Please help me with this. — PaRsH
– PaRsH, Commented Mar 26, 2014 at 7:51

Gaurang Tandon · Accepted Answer · 2014-03-26 07:55:58Z

1

/^[a-z0-9][\w\\\/]+$/i

Start of line (^).
[a-z0-9] - a letter or number - 1 occurrence
[\w\\\/]+ - multiple occurrences of alphanumeric characters (including _) or \ or /.
Line end ($).

ignore-case flag will accept both uppercase and lowercase.

[xyz] specifies a character class meaning that either x or y or z can be matched.

DEMO

If you don't consider 123_asd to be alpha-numeric, use:

/^[a-z0-9][a-z0-9\\\/]+$/i

Hope it helps!

answered Mar 26, 2014 at 7:55

Gaurang Tandon

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NeverHopeless · Accepted Answer · 2014-03-26 08:00:35Z

0

Try this regex:

(?i)^[a-z\d][a-z\d\\/]*$

?i treats upper-case letters as lower-case letters.

answered Mar 26, 2014 at 8:00

NeverHopeless

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Comments

effone · Accepted Answer · 2014-03-26 08:04:49Z

0

^[a-zA-Z0-9]+[a-zA-Z0-9\/\\]*

This will accept / or \ only in between.

Edit: Oops:p Missed the numbers, updated. Thanks for pointing out.

edited Mar 26, 2014 at 8:04

answered Mar 26, 2014 at 7:59

effone

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1 Comment

Naresh Ravlani Over a year ago

This will not accept number at start example 1a will fail. Use ^[a-zA-Z0-9]+[a-zA-Z0-9\\\/]*

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