JavaScriptCore -- Passing a function as a parameter to ObjC

Question

I have a UIWebView that utilizes JavaScriptCore. I'm trying to call an ObjC function from an web page. However, the function needs to be call asynchronously, so I'm passing in a callback function that is called when the async ObjC function is called.

It is my understanding that JS functions are equivalent to NSBlock via the bridge. The current code I have is:

context[@"currentUserLocation"] = ^( void(^callback)(NSString* str) )
{
    NSLog(@"Starting Async Function");

    //generic async function
    dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(5.0 * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
        NSLog(@"delay complete");
        callback( @"return value" );
    });
};

Is there something fundamentally wrong with what I'm doing? On the surface it seems like ObjC won't know what context to run the callback function in.

erm410 · Accepted Answer · 2014-04-12 16:16:44Z

1

It took me a little while to get the hang of this. The trick is not to think of the callback argument as a block, but a JSValue and then call it using the JSValue API:

context[@"currentUserLocation"] = ^(JSValue *callback)
{
    NSLog(@"Starting Async Function");

    //generic async function
    dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(5.0 * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
        NSLog(@"delay complete");
        //Check we actually have a callback (isObject is the best we can do, there is no isFunction)
        if ([callback isObject] != NO) {
            //Use window.setTimeout to schedule the callback to be run
            [context[@"setTimeout"] callWithArguments:@[callback, @0, @"return value"]];
        }
    });
};

Wrapping the callback in a window.setTimeout() call allows the JSVirtualMachine to take care of scheduling and threading, I have found calling the callback directly often leads to deadlocks if any UI work is done by the callback.

answered Apr 12, 2014 at 16:16

erm410

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2 Comments

TMacGyver Over a year ago

I ended up passing the function name as a string, but this answer definitely a lot better, def gona give this a try

TMacGyver Over a year ago

Can u look at this question? stackoverflow.com/questions/23047512/…

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