python regular expression to search regular pattern in file

Question

I want a function to find a pattern(word character) on each line inside a file. my code is sort of working but it does not go further after reading the first line. can anyone help? import re

    inputtext = open('input.txt', 'r+')
    inputtext1 = inputtext.read()


    match = re.search(r'([matchwordinline].*\n)+', inputtext1)



    if match:

            match1 = match.group()
    print match1

score 1 · Accepted Answer · 2014-04-03 07:15:57Z

1

re.search matches only one instance.. Try re.findall

list_name = re.findall(r'([matchwordinline].*\n)+', inputtext1)

For more Visit https://docs.python.org/2/library/re.html?highlight=matching%20searching#finding-all-adverbs

import re
inputtext = open('input.txt', 'r+')
inputtext1 = inputtext.read()

match = re.findall(r'([your word].*\n)+', inputtext1)
print match

This is my input.txt

cat
alicecat deaf
cut cat crazy
buttercup ruin
youseeacatidont

When I search for word cat i got the following output

['cat\n', 'cat deaf\n', 'cat crazy\n', 'catidont\n']

Hope this is what you meant..

edited Apr 3, 2014 at 7:15

answered Apr 2, 2014 at 6:09

user3162206

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3 Comments

user3395021 Over a year ago

your suggestion did not help. re.findall will find only the matching word. I want a given pattern following the rest of the line.

user3162206 Over a year ago

You said you want a given pattern following the rest of the line.

user3162206 Over a year ago

@user3395021 The rest of the line is available in it. Check again :)

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