check same value between two Array android

You can do it this way. Use .equals() method in String API

for (int i=0; i < b.length; i++){

    for (int j=0; j < a.length; j++){
         if(a[j].equals(b[i])){
             // a[j] matches b[i]. Perform operation when they are equal                            
         }else{
             // it doesn't match
         }
    }
}

try this . I used it for int array you can modified it for string

        int[] arr1 = {4,7,3,9,2};
        int[] arr2 = {3,2,12,9,40,32,4};
        for(int i=0;i<arr1.length;i++){
            for(int j=0;j<arr2.length;j++){
                if(arr1[i]==arr2[j]){
                    System.out.println(arr1[i]);
                }
            }
        }

Or if your using ArrayList then try below

public static void main(String[] args) {
        List<String> list_One = new ArrayList<String>();
        List<String> list_two = new ArrayList<String>();

        list_One.add("A");
        list_One.add("B");
        list_One.add("C");
        list_One.add("D");

        list_two.add("E");
        list_two.add("F");
        list_two.add("C");
        list_two.add("D");


        System.out.println("is list_two Containts List_one Elements ?");

        Iterator<String> itr =list_two.iterator();

        while(itr.hasNext()){
            String list_two_element = itr.next();

            if(list_One.contains(list_two_element)){
                System.out.println("Matching Element found in list two : " + list_two_element);
            }

        }
    }

Hope this will help you.Thanks

You could try using Collections now renames to Guava

Get the jar file from here

Since the length of the array list is different what you can do is:

1.Get the lengh of the array with the largest size

int sizeOfArrayOne = array.length;
int sizeOfArrayTwo = array2.length;

compare the sizes

2.Once you obtain which array is the largest you could then use Guava to find for you the values from another array like:

String value = Iterables.find(arrayWithLargerSize, new SearchForString(arrayOfSmallerSize[i]),null);
if(value == null) {
    // the string is not present in the array
}else {
    // the string is present in the array
}

Run this block inside a loop of the smaller array (the i represents the i for the loop).

3.Write the search predicate class like this:

class SearchForString implements Predicate<String> {
     // override the methods here
     // also ensure that you implement the correct predicate
     // one that belongs to the guava collection
}

Hope this clue suffices!

String a[]={"book","pen"};
String b[]={"pen","pencil","bottle","book","bag"};
for(int i=0;i<b.lenght;i++){
String firstValue=b[i];
for(int j=0;j<a.lenght;j++){
String secondValue=a[j];
if(firstValue.equalsIgnoreCase(secondValue)){
// item matches;
}
}
}