Deserialize JSON dynamically named field with Json.NET

Question

I get answer in JSON format from server like this (uid1, uid2...uidN - is dynamically named fields from server):

{
   "get_message_state":
   {
      "uid1":"some text 1",
      "uid2":"some text 2",
      ...
      "uidN":"some text N"
   },
   "status":"OK_Operation_Completed"
}

When I try to describe a class to deserialize json response from server, i have a problem with get_message_state field. How to describe this field in class?

public class MessageStateResponse
{
   [JsonProperty(PropertyName = "status", Order = 2)]
   public string Status { get; set; }
   [JsonProperty(PropertyName = "get_message_state", Order = 1)]
   public Msg MessageState { get; set; } //??????????
}

public class Msg
{
   [JsonProperty]
   public Dictionary<string, string> Fields { get; set; } //??????????
}

@mitomed if used code in first message, I don't have any errors, but get_message_state -> Fields is null — DaddyRatel
– DaddyRatel, Commented Apr 3, 2014 at 9:02
Are you using Json.Net? There are quite a few answers that may help you if you refine the search, for example this one stackoverflow.com/questions/19434500/… Otherwise could you put how you're using it? — mitomed
– mitomed, Commented Apr 3, 2014 at 9:17
@mitomed thanks for the link, I found the answer to my question — DaddyRatel
– DaddyRatel, Commented Apr 3, 2014 at 9:59

Aik · Accepted Answer · 2014-04-03 09:43:58Z

1

You don't have to wrap dictionary to Msg object.

public class MessageStateResponse
{
   [JsonProperty(PropertyName = "status", Order = 2)]
   public string Status { get; set; }
   [JsonProperty(PropertyName = "get_message_state", Order = 1)] 
   public Dictionary<string, string> Fields { get; set; }
}

answered Apr 3, 2014 at 9:43

Aik

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1 Comment

DaddyRatel Over a year ago

Yeah, I rewrite my code like this, it works. Thanks.

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