How do I store the size of a string in a variable

Question

I am trying to gather and store user metadata for a project, but I can not find a way to store the length (number of characters) of a string.

int main()
{
 string foo;
 int bar;
 size_t TryEverything;

 cout << "Enter some random text: ";
 getline(cin, foo);

 bar = foo.size(); //Does not work
 bar = foo.length(); //Does not work
 bar = TryEverything.size(); //Does not work
 bar = TryEverything.length(); //Does not work

}

I want bar to equal the numbers of characters (including whitespace) the user enters. Any suggestions?

I am currently using visual studio 08, and the debugger throws this error:

"Expression: deque iterator not dereferencable."

Edit:

The error was coming from somewhere else in the code. Foo should actually work.

Your TryEverything is size_t, does size_t have member size and length? — cbel
– cbel, Commented Apr 8, 2014 at 3:47
This is a simplified version of what im working on. The debugger threw up that error the second it got to line bar = TryEverything.size() so I thought I must be assigning something wrong. It might be a completely different part of my code thats broken. — user3331346
– user3331346, Commented Apr 8, 2014 at 3:55
How does bar = foo.size(); "not work" (besides probably giving you a warning about a narrowing conversion?) — juanchopanza
– juanchopanza, Commented Apr 8, 2014 at 5:20

sidrakesh · Accepted Answer · 2014-04-08 03:49:28Z

2

Try this, it worked for me:

#include<iostream>
#include<string>

using namespace std;

int main()
{
    string foo;
    size_t bar;

    cout << "Enter some random text: ";
    getline(cin, foo);

    bar = foo.size(); //Did work

    cout << bar;
}

answered Apr 8, 2014 at 3:49

sidrakesh

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Comments

herohuyongtao · Accepted Answer · 2014-04-08 03:51:20Z

1

In your code, TryEverything is of type size_t, it has no methods like size() or length().

Use

size_t sz = foo.size();

or

size_t sz = foo.length();

See it live: http://ideone.com/mHjvob.

edited Apr 8, 2014 at 3:51

answered Apr 8, 2014 at 3:46

herohuyongtao

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