Finding file directory and file name in C

Question

I have a problem with showing file directory. I used _splitpath function to cut file direction and file name. Then, I used strcat to concatenate the drive name and directory. I also used this function for file name and it was Ok. I noticed that I can't concatenate directly to drive because the buffer size of driver is only 3. So, I concatenate drive to another character array and then concatenate with directory. Here comes the problem. When I put a breakpoint and debug, there's an exception after the _splitpath line. I don't know how to fix it so, please help me with my problem.

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(int argc, char *argv[]) 
{
    char szPath[256] = {NULL};          
    char cDirCheck = '\\';                  
    char szDrive[_MAX_DRIVE] = {0};
    char szDir[_MAX_DIR] = {0};
    char szFileName[_MAX_FNAME] = {0};
    char szExt[_MAX_EXT] = {0};
    char pszPath[256] = {NULL};
    char* pszFname = NULL;

     if(cDirCheck != NULL) {
        _ splitpath(argv[0], szDrive, szDir, szFileName, szExt);
        strcat(pszPath, szDrive);
        strcat(pszPath, szDir);
        pszFname = strcat(szFileName, szExt);
        printf("\nUsage: %s fileName\n", pszFname);
        printf("EXE Path:%s", pszPath\n);
     } else {                       
        printf("\nUsage: %s fileName\n", argv[0]);
        printf("EXE Path : Current Folder\n");
    }
   return 0;
}

You may think file path and file name output correctly but the last printf of the else statement only show "EXE Path : ". I also don't know why it happened. Please give me some ideas. With regards...

BTW your program only compiles after some typos have been corrected. The test cDirCheck != NULL is always true so it is useless. But apart from that your program works fine here. You are writing about an exception after _splitpath. Tell us more about that. — Jabberwocky
– Jabberwocky, Commented Apr 11, 2014 at 6:42
When I used breakpoint and debugger as you said, "mov ecx,[esp+4]; ecx -> dest strin CXX0013: Error: missing operator" this error appeared. Please can you explain what is it about. — Newbie
– Newbie, Commented Apr 11, 2014 at 8:34
Thanks for correcting my mistakes. English is not my native language and I'm not very good at English. — Newbie
– Newbie, Commented Apr 11, 2014 at 8:38
Which operating system and which compiler/visual studio do you use ? — Jabberwocky
– Jabberwocky, Commented Apr 11, 2014 at 8:46

Jabberwocky · Accepted Answer · 2014-04-11 10:03:34Z

2

Try this. This is a stripped down version of your program that shows what is actually happening:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(int argc, char *argv[]) 
{
    char szDrive[_MAX_DRIVE] = {0};
    char szDir[_MAX_DIR] = {0};
    char szFileName[_MAX_FNAME] = {0};
    char szExt[_MAX_EXT] = {0};

    _splitpath(argv[0], szDrive, szDir, szFileName, szExt);

    printf ("argv[0]    = %s\n\n", argv[0]) ;
    printf ("szDrive    = %s\n", szDrive) ;
    printf ("szDir      = %s\n", szDir) ;
    printf ("szFileName = %s\n", szFileName) ;
    printf ("szExt      = %s\n\n", szExt) ;

    return 0;
}

argv[0] is actually the name of the command you typed in the cmd window to invoke your program. So if you type dircut, argv[0] is dircut, if you type dircut.exe, argv[0] is dircut.exe and if you type c:\xxx\dircut, argv[0] is c:\xxx\dircut and so on.

Tests:

S:\>s:\dircut\debug\dircut.exe
argv[0]    = s:\dircut\debug\dircut.exe

szDrive    = s:
szDir      = \dircut\debug\
szFileName = dircut
szExt      = .exe


S:\>s:\dircut\debug\dircut
argv[0]    = s:\dircut\debug\dircut

szDrive    = s:
szDir      = \dircut\debug\
szFileName = dircut
szExt      =


S:\>cd dircut\debug

S:\dircut\Debug>dircut.exe
argv[0]    = dircut.exe

szDrive    =
szDir      =
szFileName = dircut
szExt      = .exe

answered Apr 11, 2014 at 10:03

Jabberwocky

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2 Comments

Newbie Over a year ago

Thanks for your help, Micheal. Sorry about spending your times. I appreciate your answers.

Jabberwocky Over a year ago

That's what Stackoverflow is made for. Please accept the answer if it is what you wanted.

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