Get all nested directories in a folder python

Question

This is the directory structure

I am trying to get full path names of all the directories inside files

import os
x = os.walk('.').next()[1]

print x # prints ['33', '18', '27', '39', '2', '62', '25']

for a in x:
    y = os.walk(a).next()[1]

print y # prints ['files']

I tried a nested for but getting stopiteration error.

What I am intending to do is get something like below,

['10/files/2009','10/files/2010','11/files/2007','11/files/2010','10/files/2006']

How to do it in python?

unutbu · Accepted Answer · 2014-04-16 06:43:35Z

2

It looks like you want only the most deeply nested directories. If you use the topdown=False parameter you'll get a depth-first traversal, which will list the most deeply nested directories before their parent directories.

To filter out higher level directories, you could use a set to keep track of parent directories so as to omit reporting those:

import os

def listdirs(path):
    seen = set()
    for root, dirs, files in os.walk(path, topdown=False):
        if dirs:
            parent = root
            while parent:
                seen.add(parent)
                parent = os.path.dirname(parent)
        for d in dirs:
            d = os.path.join(root, d)
            if d not in seen:
                yield d

for d in listdirs('.'):
    print(d)

edited Apr 16, 2014 at 6:43

answered Apr 15, 2014 at 18:03

unutbu

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1 Comment

ooga Over a year ago

Why the topdown=False?

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