Ajax call to display a PHP variable

Question

I feel as if I'm making a noob mistake here, but it's annoying the hell out of me so I guess I'll post!

I'm trying to get message in the php array to be logged to the console. What actually happens is, data returns nothing, message returns 'success' and data.message is undefined.

JavaScript:

var message = '';
jQuery.ajax({
    url: '/dir/myfile.php',
    type: "POST",
    dataType: "json",
    data: { message : message },
    error: function(xhr, text, thrown){
        console.log('error');
    },
    success: function(data, message, text, xhr){

        if(data.message){
            console.log('data exists');
        } else if(message){
            console.log(message);
        }else{
            console.log('no data');
        }
    },
})

PHP:

$output = array(
    'code' => 1,
    'message' => 'Please work!'
);
echo json_encode($output);

what is your error? "If it's not obvious" ,. How is this obvious? — spiderman
– spiderman, Commented Apr 16, 2014 at 15:32
In addition to the above questions, when you navigate directly to *yourdomainhere*/dir/myfile.php, do you see the JSON output you're expecting it to hand back to the AJAX request? — tgies
– tgies, Commented Apr 16, 2014 at 15:34
you may also need to set the content type of the php script: header('Content-type: application/json') — Populus
– Populus, Commented Apr 16, 2014 at 15:39

Holt · Accepted Answer · 2014-04-16 15:33:59Z

2

According to https://api.jquery.com/jQuery.ajax/, the prototype of the success callback should be :

Function(PlainObject data, String textStatus, jqXHR jqXHR)

Anyway, you should not do a test like this :

if (data) { ... } else if (msg) { ... }

Because your message is your data !

What you want looks like that :

if (data) { console.log(data.code) ; console.log(data.message) ; }

answered Apr 16, 2014 at 15:33

Holt

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4 Comments

Purify Over a year ago

well, data returns nothing. So the alert for data doesn't get output. msg exists though and returns 'success'.

Populus Over a year ago

you should also be using the Promise object returned by .ajax call. Scroll down on api.jquery.com/jQuery.ajax to see how to use done() and fail() and always()

Holt Over a year ago

If data returns nothing, but success is call, it means the PHP script is called but output no data (or no json data). Check what your script outputs when you go to /dir/myfile.php, if you see something try to set the header content type with a header('Content-type: application/json').

Purify Over a year ago

okay, tried that. Changed to POST and it returned the JSON fine inside the PHP file. I then turned the JS back on and it went back to returning data.

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