C++ inherited functions not being found

Question

I new in C++ and I have difficulty to understand how to get my function with inheritance. I have a Class that is link to another with inheritance, everything work except:

I cannot reach my superclass function.

Here's my class header : Point.h (I don't include the .cpp):

#ifndef Point_H
#define Point_H
#include <iostream>
class Point{
  public:
         Point(); 
         void set_values (int , int);
         void set_values (int , int , int );
         void affichervaleurs();
         int getX() const { return x; }
         int getY() const { return y; }
  private:
         int x ;
         int y ;
         int z ;
  };
#endif

Now My other class that try to access the function getX from Point.h : The header : Carre.h

#ifndef Carre_H
#define Carre_H
#include "Point.h"

class Carre : public Point{      
  public:
         Carre();
         //Carre(int a , int b);
         //Carre(int a, int b):Point(a,b) {};
         //Carre(int a, int b, int c):Point(a, b, c) {};
         //const Point &pp;
         int Aire (){
         };
         void affichercar(){
                       };

  };
#endif

Carre.cpp

#include <iostream>
using namespace std;
#include "Carre.h"
#include "Point.h"

Carre::Carre():Point(){
  };
         //Carre::Carre(int a, int b);
         //const &pp;
         int Aire (){
              return (getX() * getY()); 
         };
         void affichercar(){
         //cout << "Coordonnees X:" << x  << endl;
                       };

It says that my GetX() is undeclared in my Carre.cpp . Like I said I'm new in C++ Does someone know what I'm missing to make that code work. ?

Use English names (for identifiers, comments, messages, code...) on Stack Overflow. — Basile Starynkevitch
– Basile Starynkevitch, Commented Apr 17, 2014 at 18:58
@BasileStarynkevitch They're just names and could be anything. The question's perfectly understood. — tadman
– tadman, Commented Apr 17, 2014 at 18:59
And btw, styles ... #ifndef CARRE_H also indentation in Carre.cpp — digit plumber
– digit plumber, Commented Apr 17, 2014 at 19:01

molbdnilo · Accepted Answer · 2014-04-17 19:00:06Z

3

Your definition is missing the class scope, which makes it a free function instead of a member.

It should be

int Carre::Aire (){
    return getX() * getY(); 
};

answered Apr 17, 2014 at 19:00

molbdnilo

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1 Comment

tadman Over a year ago

Right, otherwise it's declaring an independent function with no relation to the class.

qeadz · Accepted Answer · 2014-04-17 19:00:34Z

2

In the .cpp file for Carre, the functions Aire and affichercar are global. Presumably you intended:

int Carre::Aire(){
          return (getX() * getY()); 
     };

For example.

answered Apr 17, 2014 at 19:00

qeadz

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Comments

4pie0 · Accepted Answer · 2014-04-17 19:01:05Z

2

Declaring function outside class body requires a class specifier:

int Carre::Aire () {
    return (getX() * getY()); 
};

void Carre::affichercar() {
    //...
}

Otherwise

int Aire () {
    return (getX() * getY()); 
};

is just another function in global namespace that can exists simutaneously to Carre::Aire().

answered Apr 17, 2014 at 19:01

4pie0

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Comments

Velox · Accepted Answer · 2014-04-17 19:04:07Z

1

This is because you are not implementing the Aire function as being part of the Carre class.

Try changing

int Aire (){

to

int Carre::Aire (){

Also, you already have an implementation of the Aire method in the header file. You should either implement the function inline in the header file, or in the .cpp file, but not both. This also applies to your affichercar method.

answered Apr 17, 2014 at 19:04

Velox

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