XStream: How do I map xml mixed attributes and elements to POJOs?

Question

This must be a newbie question, but I could not get it from http://x-stream.github.io/.

Well, I have the following xml string

<cat age="4" >
   <name>Garfield</name>
</cat>

which needs to be mapped to:

class Cat {
  int age;
  String name;
}

Is there a simple way to do that using XStream? If not, what else could I try?

Thanks in advance.

facundofarias · Accepted Answer · 2016-08-30 09:48:55Z

3

Annotate your class like so (check http://x-stream.github.io/annotations-tutorial.html for details):

@XStreamAlias("cat")
class Cat {
  @XStreamAsAttribute
  int age;
  String name;
}

Now just use XStream as follows:

xstream = new XStream();
xstream.processAnnotations(Cat.class);
Cat roundtripGarfield = (Cat)xstream.fromXML(xstream.toXML(garfield));

edited Aug 30, 2016 at 9:48

facundofarias

3,04933 silver badges27 bronze badges

answered Feb 23, 2010 at 22:52

Christopher Oezbek

27k6 gold badges68 silver badges92 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

daveb Over a year ago

Was just writing the same thing. Add a link to the annotations docs: xstream.codehaus.org/annotations-tutorial.html

MCory Over a year ago

+1 It completely slipped my mind that there'd be an annotation for that. Should've thunk...

Christopher Oezbek Over a year ago

@MCory: No problem ;-) If you understand unmarshal you might be able to solve the question in stackoverflow.com/questions/2045290/… which I would find interesting to see answered as well.

MCory Over a year ago

Thanks Christopher -- I appreciate the tip (and feel free to check the answer to see if it's worth anything; already posted it).

anonymous Over a year ago

Thanks for the tips, by the way, without annotations xstream.aliasAttribute(Cat.class, "age", "age") also worked for me.

facundofarias · Accepted Answer · 2016-09-09 06:59:17Z

Actually, there is an answer on the XStream site -- in the Converter tutorial ;)

From http://x-stream.github.io/converter-tutorial.html:

    public Object unmarshal(HierarchicalStreamReader reader,
                    UnmarshallingContext context) {
            Birthday birthday = new Birthday();
            if (reader.getAttribute("gender").charAt(0) == 'm') {
                    birthday.setGenderMale();
            } else {
                    birthday.setGenderFemale();
            }
            reader.moveDown();
            Person person = (Person)context.convertAnother(birthday, Person.class);
            birthday.setPerson(person);
            reader.moveUp();
            reader.moveDown();
            Calendar date = (Calendar)context.convertAnother(birthday, Calendar.class);
            birthday.setDate(date);
            reader.moveUp();
            return birthday;
    }

(It's in the very last example/code block on the page.)

HTH

EDIT: Just wanted to add that you'll want to go through that whole tutorial, and not just seek out that code block. You'll need to create your own converter and register it with your XStream instance. (Probably obvious, but just in case...)

Fortyrunner · Accepted Answer · 2010-02-23 22:10:29Z

-1

You could use XPath.

Its very fast on modern JVMs and a transferable skill. E.g. you can use XPath on .NET etc

answered Feb 23, 2010 at 22:10

Fortyrunner

12.8k4 gold badges35 silver badges54 bronze badges

Collectives™ on Stack Overflow

XStream: How do I map xml mixed attributes and elements to POJOs?

3 Answers 3

5 Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

5 Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related