Get location of Powershell file that contains external function

Question

I need to call out to a powershell function defined in a file in a separate folder. That function needs to use a dll located in the same folder. Is there any easy way to do this?

Details:

Structure:

build\build.ps1
tools\myTool\fileWithFunction.ps1
tools\myTool\someDll.dll

build.ps1 has Include "...\tools\myTool\fileWithFunction.ps1"

It calls a function in that file. That function needs to load someDll.dll. I could pass the location of the folder (toos\myTool) in the function call, but was wondering if there's a way by which the function in fileWithFunction can figure out the location of the dll by itself (assuming that it's always in the same folder).

I actually have \tools\psake\psake calling build\build.ps1. Using the code in that post is giving me \tools\psake instead of \tools\myTool. — ashic
– ashic, Commented Apr 28, 2014 at 11:53

Raf · Accepted Answer · 2014-04-28 13:04:04Z

0

Use $PSScriptRoot, this should get what you need.

answered Apr 28, 2014 at 13:04

Raf

10.2k1 gold badge34 silver badges42 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Keith Hill · Accepted Answer · 2014-04-28 15:56:54Z

0

And if you're on PowerShell V2 (hopefully you're on at least v3), put this in fileWithFunction.ps1

$ScriptDir = {Split-Path $MyInvocation.ScriptName –Parent}

Then access the dir like so:

"ScriptDir is $(&$ScriptDir)"

The reason the scriptblock is used is to ensure safety when dot sourcing script files.

answered Apr 28, 2014 at 15:56

Keith Hill

204k44 gold badges370 silver badges377 bronze badges

Collectives™ on Stack Overflow

Get location of Powershell file that contains external function

2 Answers 2

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related