how can i find specific strings in string lines using regular expression in JAVA?

Question

I have three string lines here.

line 1 : 56,C0348|23064,C0319|23182,C0127|1476,C0378|2004,C0260|3306,C0091|23179,C0525|

line 2 : 8966,T4992|4446,T4992|4445,E|8965,E;T4992|8964,E;C0163|

line 3 : 920,M128;C0323|

Now, my goal is to remove strings that have a form of "Tnumber|","Cnumber|" , "Mnumber|".

For example, in the first line, i want to delete "C0348|", "C0319|", "C0127|", "C0378|", "C0260|", "C0091|", "C0525|

In the second line , T4992|, T4992, T4992|, C0163|

In the third line, M128; C0323|

How can i remove those strings from each string line?

I think i need to use regular expression, right? but, i still can not solve this problem.

Could you please help me?

ooppps sorry. the expected output will be "56,23064,23182,1476,2004,3306,23179, for the first line. — Brandon Rubinsky
– Brandon Rubinsky, Commented Apr 30, 2014 at 6:42
Rather go for a "proper" Java parser: Split the Strings on every separator (,) and then you can apply a regular expression. — Markus
– Markus, Commented Apr 30, 2014 at 6:44

thefourtheye · Accepted Answer · 2014-04-30 07:20:15Z

You can use Regular expression, like this

import java.util.regex.Pattern;

public class Test {

    private static final String REGEX = "(T|M|C)\\d+(;|\\|)?";
    private static final Pattern p = Pattern.compile(REGEX);

    public static String filterer(String inputString) {
        String result = "";
        for(String s : p.split(inputString)) {
            result += s;
        }
        return result;
    }

    public static void main(String[] args) {
        System.out.println(filterer("56,C0348|23064,C0319|23182,C0127|1476,C0378|2004,C0260|3306,C0091|23179,C0525|"));
        System.out.println(filterer("8966,T4992|4446,T4992|4445,E|8965,E;T4992|8964,E;C0163|"));
        System.out.println(filterer("920,M128;C0323|"));
    }
}

Output

56,23064,23182,1476,2004,3306,23179,
8966,4446,4445,E|8965,E;8964,E;
920,

RegEx Demo

Regular expression visualization

Debuggex Demo

Of course, instead of having capture groups, we can use character classes like this

Regular expression visualization

Debuggex Demo

songyuanyao · Accepted Answer · 2014-04-30 07:14:13Z

1

You may try a regexr of [TCM]\d+[\|;], http://regexr.com/v1?38ls3. And as java source:

String reg= "[TCM]\\d+[\\|;]";
String line = "56,C0348|23064,C0319|23182,C0127|1476,C0378|2004,C0260|3306,C0091|23179,C0525|";
line = line.replaceAll(reg, "");
System.out.println(line);
line = "8966,T4992|4446,T4992|4445,E|8965,E;T4992|8964,E;C0163|";
line = line.replaceAll(reg, "");
System.out.println(line);
line = "920,M128;C0323|";
line = line.replaceAll(reg, "");
System.out.println(line);

output:

56,23064,23182,1476,2004,3306,23179,
8966,4446,4445,E|8965,E;8964,E;
920,

edited Apr 30, 2014 at 7:14

answered Apr 30, 2014 at 6:46

songyuanyao

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3 Comments

songyuanyao Over a year ago

@user3149929 In the third line, "M128;" should be deleted? But you said the rule is "Mnumber|", so the rule should be "Mnumber;"?

Brandon Rubinsky Over a year ago

sorry, my mistake. So, expression would be [TCM]\\d+(;|\\|)?. right?

songyuanyao Over a year ago

? means "Zero or one", so if "\" or ";" must appears once, it should be "[TCM]\\d+[\\|;]". I've edited my post.

Scary Wombat · Accepted Answer · 2014-04-30 06:46:19Z

0

as these are comma delimitered values you can split them as

String arr[] = line.split (",");

// iterate over them
int index = arr[0].indexOf ("|");
if (index != -1) {

   // do substring
}

answered Apr 30, 2014 at 6:46

Scary Wombat

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