Replace regExp with certain characters (Javascript)

Question

I have having some issues trying to replace a certain group of special characters in a string. Specifically

str = 'This is some demo copy[300]this should remove the brackets and the copy 300.'

I have been trying to replace it with

str.replace(/[300]/g, "<br />");

with no such luck. I seem to be getting hung on with the brackets[] that also need to be removed. I know that I can remove them individually, and then replace the 300 but I need to replace the set together.

It should return:

This is some demo copy
this should remove the brackets and the copy 300.

Any advice would be extremely appreciative as I am relatively new to regular expressions.

Thanks in advance!

Paul Roub · Accepted Answer · 2014-05-07 16:16:47Z

4

In regular expressions, [ and ] have special meaning. You're asking to replace any 3 or 0 that might be found.

Escape the brackets like so:

str.replace(/\[300\]/g, "<br />");

answered May 7, 2014 at 16:16

Paul Roub

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VisioN · Accepted Answer · 2014-05-07 16:15:40Z

0

Here is a regex for you:

/\[300\]/g

Brackets in regular expressions language define a character set. In your case you simply need to escape them to make things working.

answered May 7, 2014 at 16:15

VisioN

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2 Comments

Paul Roub Over a year ago

That would also replace the bare "300" at the end (since you made the brackets optional), which isn't what the OP is after.

VisioN Over a year ago

Hm.. I was sure he wants to replace both, whenever there are brackets or there are not. Most probably I misread. Anyway, if so, just removed ?.

Mike Cluck · Accepted Answer · 2014-05-07 16:17:12Z

0

You need to escape your square brackets.

str.replace(/\[300\]/g, "<br />");

answered May 7, 2014 at 16:17

Mike Cluck

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