Django object filtering with variables

Question

I have model that looks like this:

class Beacon(models.Model):
    name = models.CharField()
    bid =  models.CharField()
    campaigns = models.ManyToMany(Campaign)
    location = models.ForeignKey(Location)

In my api view, I am trying to find a specific Beacon given a bid (this is beacon id btw). So I have something that looks like this:

def SawBeacon(request, beacon_id):

    if request.method == 'GET':
        Beacon  = Beacon.objects.filter(bid__beacon_id=%s) % beacon_id

This doesn't work.. But I think you get the idea of what I am trying to do. I want to take the incoming beacon_id argument and filter down to a specific beacon that matches this ID.

How would I do this?
When I filter down an object, do I get the object itself or will I get the value?

What about: Beacon.objects.filter(bid__beacon_id=(%s) % (beacon_id))? — felipsmartins
– felipsmartins, Commented May 14, 2014 at 16:46
Question: I actually don't know if the "bid__beacon_id" part is correct. More specifically the "beacon_id" part .I am just copying previous examples. — ApathyBear
– ApathyBear, Commented May 14, 2014 at 17:01

Alex · Accepted Answer · 2014-05-14 16:51:55Z

2

If you're getting one instance, you'll want to use get rather than filter. Try:

Beacon.objects.get(bid=beacon_id)

When you use filter, you'll return a queryset.

answered May 14, 2014 at 16:51

Alex

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4 Comments

Rod Xavier Over a year ago

I think he's actually looking for Beacon.objects.get(id=beacon_id)

Alex Over a year ago

But isn't bid his field for beacon_id?

Alex Over a year ago

Correct. Filter returns a queryset, even if there's only one instance in the queryset.

Llanilek Over a year ago

Get will also throw an error if the object doesn't exist so you should always anticipate this with a try except statement. You can use django.core.exceptions ObjectDoesNotExist to check for this.

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