Get a image height according to width using php

Question

I want to get a image size according to the width and also I'm resizing the width if more then 500px

Here is my code so far

list($width, $height) = getimagesize("MyImage.jpg");

if ($width<300){
    $NewWidth = $width;

}else{ 
    $NewWidth = '500';

}

Just like to know how to get new height according to the width. Really appreciate your help or any advice you can give.

Are you talking about proportional scaling? Like in doing math? — PeeHaa
– PeeHaa, Commented May 17, 2014 at 12:44
@PeeHaa yes even if you can tell me the math that will be fine. — maxlk
– maxlk, Commented May 17, 2014 at 12:45

Nathan Dawson · Accepted Answer · 2014-05-17 12:54:44Z

3

You need to get current image scale and then use that to calculate the new height from the new width. Divide the width by the height to get the scale. Then divide the new width by the scale to get the new (proportional) height.

list($width, $height) = getimagesize("MyImage.jpg");

// Get the image scale.
$scale = $width / $height;

// Existing width modification.
if ($width<300){
    $NewWidth = $width;

}else{ 
    $NewWidth = '500';

}

// Get new height from new width.
$NewHeight = $NewWidth / $scale;

answered May 17, 2014 at 12:54

Nathan Dawson

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Comments

pratik nagariya · Accepted Answer · 2014-05-17 12:57:41Z

0

Try this formula to maintain 4:3 aspect ratio.

new height = ((width X 3) / 4)

edited May 17, 2014 at 12:57

answered May 17, 2014 at 12:52

pratik nagariya

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6 Comments

maxlk Over a year ago

don't you need the original height also to get the correct new height?

pratik nagariya Over a year ago

No, It does not required.

Nathan Dawson Over a year ago

@pratiknagariya You're misunderstanding the OPs question. He's not asking how to get maintain a 4:3 ratio.

pratik nagariya Over a year ago

@Nathan Dawson For the correct height we have to maintain image resolution ratio and 4:3 is the standard for image. And that can be changed based on the requirement.

Nathan Dawson Over a year ago

That's wrong. Please see my answer. The OP never stated the image was 4:3. You need to detect the scale not force it

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