python requests library not returning any response

Question

When I try the following code, requests library not returning any response

import requests
url = "http://www.nodefarm.com/"
resp = requests.get(url, timeout=5.0)
print resp

Can someone tell me why my code got stuck in line 3?

P.S: I'm not receiving any error.

When I visit http://www.nodefarm.com/ in my browser, site works fine

do you have the requests library installed? is the location of the install in your python path? — deweyredman
– deweyredman, Commented May 30, 2014 at 0:54
If he didn't, he would get an import error on line 1. It wouldn't even make it to the line he gets stuck on. — Gerrat
– Gerrat, Commented May 30, 2014 at 0:55
@deweyredman Yes I have that library installed. I'm using that library for months. All other urls working except this one. Its just 3 lines of code. So you may test that in your shell. — PrivateUser
– PrivateUser, Commented May 30, 2014 at 1:01
Reason why I was asking is because context would be nice...For example is this is on a windows system and python hasn't been whitelisted through the firewall that might explain what's going on. — deweyredman
– deweyredman, Commented May 30, 2014 at 1:01

SingleNegationElimination · Accepted Answer · 2014-05-30 01:04:41Z

4

well, the thing is, it's not exactly getting stuck.

that url returns an apparently endless stream of data, the first few lines of which look a bit like so:

ICY 200 OK
icy-notice1:<BR>This stream requires <a href="http://www.winamp.com/">Winamp</a><BR>
icy-notice2:SHOUTcast Distributed Network Audio Server/Linux v1.9.8<BR>
icy-name:RADIO HANG 106  FM BATAM - SVR USA
icy-genre:Misc
icy-url:http://live.hang106.com/;stream.nsv
content-type:audio/mpeg
icy-pub:1
icy-br:48

Pulling it up in vlc, it seems to be talk radio in a language I don't speak.

answered May 30, 2014 at 1:04

SingleNegationElimination

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1 Comment

PrivateUser Over a year ago

Ok. Can you tell me how to handle this problem in my program?

kai · Accepted Answer · 2014-05-30 01:10:05Z

4

IfLoop is correct that the page is streaming data. You can use requests with stream=True and iterate to see the data for yourself:

import requests
url = "http://www.nodefarm.com/"
resp = requests.get(url, stream=True)
for line in resp.iter_lines():
    if line:
        print line

Not sure how much this will help though.

answered May 30, 2014 at 1:10

kai

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