Using variables inside functions that are in a class

Question

Im trying to call a variable that is being created in the function , how can i access this variable?

<?php

class youtube
{
    public function details()
    {
           $test = "asdas";
    }
}
$class = new youtube();
$s = $class->details()->test;
echo $s;
?>

Head back to the PHP documentation on classes and objects basics and specifically on object properties — Michael Berkowski
– Michael Berkowski, Commented May 31, 2014 at 3:26

Turnerj · Accepted Answer · 2014-05-31 03:27:30Z

2

There is a couple of ways you can do it however I would do something like this.

<?php

class youtube
{
    private $details = array(
        'test' => null
    );
    public function details()
    {
        return $this->details;
    }
}

$class = new youtube();
$s = $class->details()->test;
echo $s;

Basically I am storing a details property which contains various properties and I just return this object.

answered May 31, 2014 at 3:27

Turnerj

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1 Comment

Turnerj Over a year ago

I will note that there is many acceptable ways of returning the variable. I am just highlighting one way where you can return an object of data that is otherwise concealed in the class (eg. private)

hammus · Accepted Answer · 2014-05-31 03:27:48Z

1

As @Feroz has suggested, you're not returning anything from the details() method:

class youtube
{
    public function details()
    {
           $test = "asdas";
           return $test;
    }
}
$class = new youtube();
$s = $class->details();
echo $s;

or

class youtube
{
    public $test;
    public function details()
    {
           $this->test = "asdas";
           return $this;
    }
}
$class = new youtube();
$s = $class->details()->test;
echo $s;

Further reading on variable scope can be found in the documentation.

answered May 31, 2014 at 3:27

hammus

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1 Comment

hammus Over a year ago

There are myriad ways to do it, but as @MichaelBerkowski has suggested, a good refresh in PHP (and programming) basics might serve you well.

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