Capture header in PHP-CGI

Question

I'm attempting to get all HTTP header output from a PHP file, when run via php-cgi. From everything I've read, php-cgi is supposed to output all headers by default. (There's even an option to suppress this, as though it happens automatically.)

I have a PHP file named "test.php", with the following contents:

header('Location: http://stackoverflow.com');
echo 'test';

But when I run it:

php-cgi -f test.php

The output is simply:

test

I expected the location header to be output first. How can I get this header info? I'm using PHP 5.5.3-1ubuntu2.3 (cgi-fcgi).

You should put an exit(); after your header(...);. It's logical that "test" is the output of your script. Read this : stackoverflow.com/questions/3553698/… — Vincent Decaux
– Vincent Decaux, Commented Jun 1, 2014 at 19:08

gavanon · Accepted Answer · 2014-06-02 03:47:59Z

2

I got it! I noticed in the doc definition for the -f argument that it "Implies '-q'".

So this is the solution:

php-cgi test.php

(Without the -f argument)

answered Jun 2, 2014 at 3:47

gavanon

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viralpickaxe · Accepted Answer · 2014-06-01 19:12:05Z

-1

The problem is that you are not exiting the script once setting header. You would need to do something more like this

header('Location: http://stackoverflow.com');
exit();

otherwise code after the header() will be run aswell

answered Jun 1, 2014 at 19:12

viralpickaxe

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1 Comment

gavanon Over a year ago

Thanks - that won't help either. I figured it out though, but can't answer my own question as a new user. Turns out the problem was the -f argument when calling php-cgi. Docs say "Implies -q", which suppresses headers!

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