php unique rand() inside set of numbers

Question

I am trying to put a load of images in a random order using php this is what I have tried

for ($i=47; $i < 54; $i++) {
            echo "<img width='205' src='IMG_03";
            echo rand(47,53);
            echo ".jpeg' alt=''>";  
}

But this code includes duplicates how could I do this without having the same random number between 47 and 53 twice?

$values = range(47,53); shuffle($values);

Mark Baker
– Mark Baker

2014-06-05 21:58:29 +00:00
Commented Jun 5, 2014 at 21:58 — Mark Baker
– Mark Baker, Commented Jun 5, 2014 at 21:58

barell · Accepted Answer · 2014-06-05 21:58:30Z

1

<?php

$numbers = range(47, 54);
shuffle($numbers);

foreach($numbers as $n) {
    echo '<img src="IMG_03'.$n.'.jpg" alt="" />';
}

answered Jun 5, 2014 at 21:58

barell

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Comments

Mark Miller · Accepted Answer · 2014-06-05 22:04:12Z

1

Try this:

$array = range(47, 53);
shuffle($array);

foreach ($array as $a) {
    echo "<img width='205' src='IMG_03";
    echo $a;
    echo ".jpeg' alt=''>";  
}

range() creates an array of numbers between the given values: 47, 48, ..., 53

shuffle() puts it in random order

edited Jun 5, 2014 at 22:04

answered Jun 5, 2014 at 21:58

Mark Miller

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Comments

Martin Konecny · Accepted Answer · 2014-06-05 21:59:07Z

0

Use the shuffle method

$arr = array(47, 48, 49, 50, 51, 52, 53);

shuffle($arr);

while($element = array_pop($arr)){
    echo "<img width='205' src='IMG_03";
    echo $element;
    echo ".jpeg' alt=''>";  
}

answered Jun 5, 2014 at 21:59

Martin Konecny

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