PHP form values after POST

Question

I have a form on which I POST the data with PHP. When the data is send I want to show the new values. Doing this on textfields is easy, but how can I set the new values on the radioboxes. My default value is Male here.

PHP

if (isset($_POST['Submit'])) {
    update_user($_POST['name'], $_POST['sex']); // the update method
}

HTML

<form name="form1" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
  <label for="name">Name:</label>
  <input type="text" name="name" size="30" value="<?php echo (isset($_POST['name'])) ? $_POST['name'] : ""; ?>">
  <br /><br />
  <label for="sex">Sex:</label>
  <input type="radio" checked="checked" name="sex" value="<?php echo (isset($_POST['sex'])) ? $_POST['sex'] : "M"; ?>" /> Male
  <input type="radio" name="sex" value="<?php echo (isset($_POST['sex'])) ? $_POST['sex'] : "F"; ?>" /> Female
</form>

You have to add checked = "checked" if value is selected. Check the answers for details. — Ignacio
– Ignacio, Commented Mar 11, 2010 at 13:55

Davide Gualano · Accepted Answer · 2010-03-11 13:53:41Z

2

<input type="radio" <?php if ($_POST['sex'] == "M") print "checked=\"checked\"";?> name="sex" value="M" /> Male
<input type="radio" <?php if ($_POST['sex'] == "F") print "checked=\"checked\"";?> name="sex" value="F" /> Female

answered Mar 11, 2010 at 13:53

Davide Gualano

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Comments

Aaron W. · Accepted Answer · 2010-03-12 12:18:57Z

1

Well you know the values of the Sex radioboxes...M and F. You want to see which one needs to be checked. This will default the checked to be Male like you currently have it.

<input type="radio" <?php echo (!isset($_POST['sex']) || $_POST['sex'] == "M") ? 'checked="checked"': ''; ?> name="sex" value="M" /> Male
<input type="radio" <?php echo (isset($_POST['sex']) && $_POST['sex'] == "F") ? 'checked="checked"': ''; ?> name="sex" value="F" /> Female

edited Mar 12, 2010 at 12:18

answered Mar 11, 2010 at 13:56

Aaron W.

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1 Comment

TunaFFish Over a year ago

Actually Aarons example is exactly what I wanted, with default "M" checked. Typo though for the statement () ? :, not ;

Andy E · Accepted Answer · 2010-03-11 13:54:49Z

0

Try the following instead:

<form name="form1" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> 
  <label for="name">Name:</label> 
  <input type="text" name="name" size="30" value="<?php echo (isset($_POST['name'])) ? $_POST['name'] : ""; ?>"> 
  <br /><br /> 
  <label for="email">Sex:</label> 
  <input type="radio" name="sex"<?php echo (@$_POST['sex'] == "M") ? 'checked="checked"' : "";?> value="M" /> Male 
  <input type="radio" name="sex" <?php echo (@$_POST['sex'] == "F") ? 'checked="checked"' : "";?> value="F" /> Female 
</form>

Using the @ character means you don't need to use isset, it will suppress the warnings/errors if the variable isn't in the $_POST array.

answered Mar 11, 2010 at 13:54

Andy E

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Comments

Pablo Morales · Accepted Answer · 2010-03-11 13:53:22Z

-2

Try with print_r( $_POST );exit; to see the values sending in the variable POST.

answered Mar 11, 2010 at 13:53

Pablo Morales

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