Python for loop error

Question

I'm working on a Python exercise at Codecademy and got stuck on what looks like a simple problem:

Write a function fizz_count() that loops through all the elements of a list. When the element is 'fizz', increment a counter called count. Then return the value of count.

My code:

def fizz_count(x):
  count = 0
  for i in x:
    if x[i] == 'fizz':
      count = count + 1
  return count

I get this error message:

An exception was raised for fizz_count(['fizz', 'buzz']): list indices must 
be integers not str

Everything is formatted exactly as shown. I can't figure out where the error is.

The error tells you exactly where the error is - if the list index must be an integer, but is actually a string, then i is a string. Why not print i to find out why? — jonrsharpe
– jonrsharpe, Commented Jun 21, 2014 at 9:04

Christian Tapia · Accepted Answer · 2014-06-21 08:59:13Z

4

If x is a sequence of elements, when you do

for i in x:

you are looping through the elements of x, not through indexes.

So when you do

x[i]

you are doing

x[element]

which makes no sense.

What can you do?

You can compare the element with 'fizz':

for element in x:
    if element == 'fizz':
        # ...

answered Jun 21, 2014 at 8:59

Christian Tapia

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1 Comment

MNRC Over a year ago

Yeah, I just figured it out. This is not C++ :P Thanks!

Padraic Cunningham · Accepted Answer · 2014-06-21 08:59:02Z

3

You are passing in a list ['fizz', 'buzz']) so i is equal to fizz or buzz not an integer. Try if i =="fizz"

def fizz_count(x):
  count = 0
  for i in x:
    if i  == 'fizz': # i will be each element in your list
      count = count + 1
  return count

answered Jun 21, 2014 at 8:59

Padraic Cunningham

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Comments

DOSHI · Accepted Answer · 2014-06-21 09:45:25Z

0

When you used { for i in x } then here 'i' is the item of the list and not an index. Hence,

Corrected Code is:

def fizz_count(x):
  count = 0
  for i in x:
    if i == 'fizz':
      count = count + 1
  return count

print fizz_count(['fizz', 'buzz'])

OUTPUT

answered Jun 21, 2014 at 9:45

DOSHI

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