Why doesn't my array store any input values?

Question

I want to input any number into array b[] by number of numCase times.

#include <iostream>
using namespace std;

//entry point

int main()

{


//Declarations

int b[20]; // array size 20 ( limit of inputs)
int c = 0;
int numCase;
int input;





 cout << "ENTER NUMBER OF CASES (MAXIMUM NUMBER OF 20):  \n";
 cin >> numCase;


//checks that numCase is less than or equal to (20) and does not exceed
if (numCase < 21)
        {



// gets input number based on the numCase

do
{


cout << "ENTER A NUMBER (MAXIMUM OF 5 DIGITS): \n";
                cin >> input;
                cout << "\n";
                b[c] = input;
                c++;



} while (c != numCase);


cout << b[c] ;  //  this is my problem it OUTPUTS RANDOM VALUE, 
     //but i can  see on my watch list that b has the values of my input.
}

}

RichieHindle · Accepted Answer · 2014-06-23 07:47:02Z

2

You're filling entries 0 toN of b, and then printing entry N+1, which you haven't filled in.

answered Jun 23, 2014 at 7:47

RichieHindle

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2 Comments

user3739376 Over a year ago

what changes should i make?

zoska Over a year ago

Print entry of index one less than when printing b[c]

suspectus · Accepted Answer · 2014-06-23 07:46:50Z

1

The variable c should be initialised back to zero.

} while (c != numCase);

c = 0;

answered Jun 23, 2014 at 7:46

suspectus

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6 Comments

user3739376 Over a year ago

I tried your suggestion i initialized c to 0 after the while loop but when i cout b[c] all i got was the first input. say i wanted 2 inputs ex. 20 and 700 my cout only displayed 20.

suspectus Over a year ago

Yes - best use a for loop and increment a counter to display all array elements.

user3739376 Over a year ago

should i want to use if statements i.e. if ( b[counter] <101) and my inputs are 20 and 700. how do i make sure that 700 doesn't get inside that statement? i've tried it 700 does get inside

suspectus Over a year ago

if (b[counter] <= 700) ?

user3739376 Over a year ago

the problem is that 700 is not less than 101 already, but since b[counter] also contains 20 it also runs 700 inside the statement, what can i do to make sure that doesn't happened?

|

rajenpandit · Accepted Answer · 2014-06-23 07:47:42Z

0

cout << b[c] ; // in this statement c already reached to numCase where you have not assigned any value

answered Jun 23, 2014 at 7:47

rajenpandit

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Comments

KennethLJJ · Accepted Answer · 2014-06-23 09:36:27Z

0

I think this is what you might be looking for:

for (int i=0; i<numCase; i++)
{
    if(b[i] >= x) //x is a variable that u can set as a limit. eg. 700
    {
        cout<<"\n"<<b[i];
    }
}

Hope it helps

answered Jun 23, 2014 at 9:36

KennethLJJ

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Comments

Shubham · Accepted Answer · 2014-06-23 10:12:15Z

0

If you want to display all the numbers stored in array b[] then you may write your code as

for(int i=0;i<=20;i++)
{ if(b[i]<101)   //This will exclude all the values which are greater than 101
   {cout<<"\n"<<b[i];}}

edited Jun 23, 2014 at 10:12

answered Jun 23, 2014 at 8:27

Shubham

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2 Comments

user3739376 Over a year ago

i've tried the for loop and it does display all my inputs. but should i want to use if statements i.e. if ( b[counter] <101) and my inputs are 20 and 700. how do i make sure that 700 doesn't get inside that statement? i've tried it 700 does get inside

Shubham Over a year ago

I've edited my answer. I hope you might want to do this.

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