continue foreach loop from a specific point within array

Question

I have an array containing lots of hours:

$hours = array(
    '06:00', '06:30', '07:00', '07:30', '08:00', '08:30', '09:00', '09:30', 
    '10:00', '10:30', '11:00', '11:30', '12:00', '12:30', '13:00', '13:30', 
    '14:00', '14:30', '15:00', '15:30', '16:00', '16:30', '17:00', '17:30', 
    '18:00', '18:30', '19:00', '19:30', '20:00', '20:30', '21:00', '21:30',
    '22:00', '22:30', '23:00', '23:30', '00:00', '00:30', '01:00', '01:30', 
    '02:00', '02:30', '03:00', '03:30', '04:00', '04:30', '05:00', '05:30', 
);

I'd like to begin looping through from a specific point e.g. '12:30'.

I have tried to use 'continue' (as below), but this is ignored. Any ideas what I am doing wrong?

foreach ($hours as $hour) {
     if ($hour == '12:30') continue;
     echo $hour . '<br>';
}

Can you debug when $hour is '12:30'? What does the if block result to when it compares '12:30' to '12:30'? — MrMike
– MrMike, Commented Jun 27, 2014 at 23:49
So your goal is to output all times from 12:30 forward, (or not including 12:30)? — Michael Berkowski
– Michael Berkowski, Commented Jun 27, 2014 at 23:51
Ok, well your for loop says in English, "go through each hour in the array. If hour is '12:30', continue to the next iteration, ignoring everything else in the loop. Otherwise, echo the hour and a line break." It is not skipping everything until 12:30 — MrMike
– MrMike, Commented Jun 27, 2014 at 23:53
No the value shouldn't occur more than once as it's in 24 hr times. — user1444027
– user1444027, Commented Jun 27, 2014 at 23:55

FuzzyTree · Accepted Answer · 2014-06-27 23:53:02Z

1

$hours = array(
    '06:00', '06:30', '07:00', '07:30', '08:00', '08:30', '09:00', '09:30', 
    '10:00', '10:30', '11:00', '11:30', '12:00', '12:30', '13:00', '13:30', 
    '14:00', '14:30', '15:00', '15:30', '16:00', '16:30', '17:00', '17:30', 
    '18:00', '18:30', '19:00', '19:30', '20:00', '20:30', '21:00', '21:30',
    '22:00', '22:30', '23:00', '23:30', '00:00', '00:30', '01:00', '01:30', 
    '02:00', '02:30', '03:00', '03:30', '04:00', '04:30', '05:00', '05:30', 
);

$start = array_search('12:30',$hours);

foreach($hours as $key => $hour) {
    if($key < $start)
        continue;

    print "$hour\n";
}

Or as suggested in comments (and this is faster)

$start = array_search('12:30',$hours);

for($i = $start; $i < count($hours); $i++) {
    print $hours[$i] . "\n";
}

answered Jun 27, 2014 at 23:53

FuzzyTree

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2 Comments

Michael Berkowski Over a year ago

Probably better to just use an incremental for loop starting from $start up to count($hours) instead of bothering with continue, looping over stuff which isn't needed.

Michael Berkowski Over a year ago

..but yes, array_search() is the way to do this.

bloodyKnuckles · Accepted Answer · 2014-06-27 23:56:35Z

0

First find the key referring to '12:30', and, if found, loop over the $hours array starting at that key.

if ( $key = array_search('12:30', $hours) ) {
  for ( ; $key < count($hours); $key++ ) {
    print $hours[$key] . '<br>'; 
  } 
}

answered Jun 27, 2014 at 23:56

bloodyKnuckles

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Comments

Barmar · Accepted Answer · 2014-06-27 23:55:40Z

0

Change to:

if ($hour < '12:30') {
    continue;
}

Your code just skips that one time, it doesn't skip all the ones before it.

Another way to do it is to get the position of the desired hour, and use a normal for loop:

foreach ($i = array_search('12:30', $hours); $i !== false && $i < count($hours); $i++) {
    $hour = $hours[$i];
    echo $hour . "<br";
}

answered Jun 27, 2014 at 23:55

Barmar

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