I'm trying to create an array of tuples in Swift, but having great difficulty:
var fun: (num1: Int, num2: Int)[] = (num1: Int, num2: Int)[]()
The above causes a compiler error.
Why's that wrong? The following works correctly:
var foo: Int[] = Int[]()
It works with a type alias:
typealias mytuple = (num1: Int, num2: Int)
var fun: mytuple[] = mytuple[]()
// Or just: var fun = mytuple[]()
fun.append((1,2))
fun.append((3,4))
println(fun)
// [(1, 2), (3, 4)]
Update: As of Xcode 6 Beta 3, the array syntax has changed:
var fun: [mytuple] = [mytuple]()
// Or just: var fun = [mytuple]()
You can do this, just your assignment is overly complicated:
var tupleArray: [(num1: Int, num2: Int)] = [ (21, 23) ]
or to make an empty one:
var tupleArray: [(num1: Int, num2: Int)] = []
tupleArray += (1, 2)
println(tupleArray[0].num1) // prints 1
var tupleArray: (num1: Int, num2: Int)[] = [] just works.
This also works:
var fun:Array<(Int,Int)> = []
fun += (1,2)
fun += (3,4)
Oddly though, append wants just one set of parens:
fun.append(5,6)
If you want the labels for the tuple parts:
var fun:Array<(num1: Int, num2: Int)> = []
fun += (1,2) // This still works
fun.append(3,4) // This does not work
fun.append(num1: 3, num2: 4) // but this does work
Not sure about earlier versions of Swift, but this works in Swift 3 when you want to provide initial values:
var values: [(num1: Int, num2: Int)] = {
var values = [(num1: Int, num2: Int)]()
for i in 0..<10 {
values.append((num1: 0, num2: 0))
}
return values
}()
As of Swift 5.7, the following works.
/* Create empty array of (num1: Int, num2: Int) tuples */
var array1 = [(num1: Int, num2: Int)]()
/* Can be populated with (Int, Int) tuples
(the labels are optional)... */
for i in 1...8 {
array1.append((i, i*i))
}
/* ...or (num1: Int, num1: Int) tuples */
for i in 9...12 {
array1.append((num1: i, num2: i*i))
}
Array(repeating: <value>, count:):var array2 = Array(repeating: (num1: 0, num2: 0), count: 8)
It can be done like this as well.
var arr : [(num1: Int, num2 : Int)] = {
let arr = Array(repeating: (num1: 0, num2 :0), count : n)
return arr
}()
