Why does obj.constuctor.name give 2 different results if prototype is missing? How do i get the constructor name instead of "Object" if it has prototype then?
// Class with prototype
function Foo(a) {
this.a = a;
}
Foo.prototype = {
bar: function () {
console.log(this.a);
}
};
f=new Foo(1)
f.constructor.name
"Object"
// Class with no prototype
function Fooee(a) {
this.a = a;
}
f1=new Fooee(1)
f1.constructor.name
"Fooee"
You're changing the constructor of Foo() by redefining its prototype to object {}.
You should've instead done this:
Foo.prototype.bar = function () {
console.log(this.a);
}
Functions’ prototype properties have initial values that include constructor. You can try it:
function Foo() {
}
assert(Foo.prototype.constructor === Foo);
When you overwrite the entire prototype with an object, you’re clobbering that property. ({}.constructor === Object.) Just assign new properties to it instead:
Foo.prototype.bar = function () {
console.log(this.a);
};
