Suppose i have this list a = ["test", "news", "hello"] and i need to duplicate each value in list and separate it by delimiter like this.
a = [("test","test"),("news","news"),("hello","hello")]
I have tried this and got only up to this.
a = ["test", "news", "hello"]
b = [l + (''.join(l,)) for l in a]
print(b)
#['testtest', 'newsnews', 'hellohello']
You can do it as:
a = ["test", "news", "hello"]
>>> print [(i,)*2 for i in a] #thanks to @JonClements for the suggestion
[('test', 'test'), ('news', 'news'), ('hello', 'hello')]
(i,)*2 for flexibility (for increasing the amounts if ever needed)[','.join((i,) * 2) for i in a]I think the most "pythonic" (and shortest) way to do this is with everyone's favorite confusing built-in, zip:
a = ["test", "news", "hello"]
print zip(a,a)
>>> [('test', 'test'), ('news', 'news'), ('hello', 'hello')]
And, for completeness, I'll point out that in python 3, zip returns an iterable. So to get it to print nicely, you'll want to listify it: list(zip(a,a)). If, however, you want to iterate through it, doing things with the data, you'll want to keep the iterable. (Potentially massive memory savings for long lists).
,for each element...