Regex: Not empty - no letters

Question

I'm rather new to Regex, and i'm working on this particular statement:

The input can't be empty, and it cannot contain any letters ([a-zA-Z]).

I have these 2 statements now:

Not empty: (?=\\s*\\S).*$)
No letters: ^[^a-zA-Z]

I know these 2 work. However, i need to combine them in a single statement (for use with Javascript). I have tried literally everything i can find and can think of. Putting the statements between ()'s, between []'s, separating them with |, combining them with ()(), adding and removing ^ and *$, and every combination thereof. However, it always seems to either be not empty or no letters, never both.

Can anyone help me combine these 2 statements into 1?

/^[^a-zA-Z]+$/ - the + ensures there's at least one character. — Niet the Dark Absol
– Niet the Dark Absol, Commented Jul 7, 2014 at 11:51
Thanks Absol, that indeed did the trick. I can't believe i just spend hours trying to combine it when it was a simple '+'. Now that i'm typing another question about Regex: Why is it that people always post regex as /regexHere/, but when i use the code i have to remove the /'s? What's the point in typing it with a single /? — Davy
– Davy, Commented Jul 7, 2014 at 11:57
@Mortaza: Regular expressions are often written with forward slashes as delimiters. For example, /re/ is used for the regular expression re. Several languages, including JavaScript, use the same delimiter notation. See this answer for an example. Check Wikipedia for a brief history of how this came into existence. — Amal
– Amal, Commented Jul 7, 2014 at 12:06

Husman · Accepted Answer · 2014-07-07 11:55:54Z

5

Try the following:

/^[^a-zA-Z]+$/

(note: Niet the Dark Absol commented exactly what I just posted here, before I answered, so if you want to I'll delete my answer so you can pick up the upvotes.)

answered Jul 7, 2014 at 11:55

Husman

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1 Comment

Davy Over a year ago

This one works :) Absol posted it first in the comment part, but i'll accept your answer for future references.

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