Using .indexOf() in an if statement in java

Question

I need to use an indexof method but terminal is telling me that it needs a variable but it gets a value. Can you guys explain how I fix this?

This is what I came up with by myself.

char a = 'a';
    if (s.indexOf(a, s.length()) == 61)
        System.out.println(" Your string contains the letter 'a' at index position: " + s.indexOf(97));
    else
        System.out.println(" Your string does not contain the letter 'a'");

The tags you added are all irrelevant. Looks like Java to me. — Felix Kling
– Felix Kling, Commented Jul 8, 2014 at 3:54

Pham Trung · Accepted Answer · 2014-07-08 04:33:54Z

2

If you are using Java. Method indexOf return the first position in string s that contains the string you pass in the method. It returns -1 if the string is not found.

if (s.indexOf("a") >= 0)
        System.out.println(" Your string contains the letter 'a' at index position: " + s.indexOf("a"));
    else
        System.out.println(" Your string does not contain the letter 'a'");

edited Jul 8, 2014 at 4:33

answered Jul 8, 2014 at 3:55

Pham Trung

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4 Comments

WeekzGod Over a year ago

thanks a lot this worked but I don't understand why. Can you explain it to me?

gprathour Over a year ago

@WeekzSO If it worked, you should accept the answers. It will help others too who might face the same problem.

Pham Trung Over a year ago

@WeekzSO I added a link to the java API and also a brief explanation :)

WeekzGod Over a year ago

@GPRathour i can't accept the answer for another 6 minutes.

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