Print Tuple Index in Python

Question

This question falls into the "yes - this works, yes - this is ugly, yes - there is probably a better way" category. I want to use a regular expression to pull groups out of a match and then print the group number and the group value. It is to show someone how regular expressions work and to keep track of the values of each group. The code that works is:

import re

FundTypeGroups = re.match("([A-Z]0)(\d)([A-Z])","G02A").groups()
print FundTypeGroups

for FundTypeGroup in FundTypeGroups:
    print "%s: %s" % (FundTypeGroups.index(FundTypeGroup), FundTypeGroup)

Is there a better way to print the index of each tuple entry?

Never use capital letters as the first letter of a variable unless it refers to a class. — Mike Graham
– Mike Graham, Commented Mar 17, 2010 at 18:26
Instead of you hitting each style faux paux one at a time look at pep 8 for style guidance. python.org/dev/peps/pep-0008 — Paul Hildebrandt
– Paul Hildebrandt, Commented Mar 18, 2010 at 0:26

kennytm · Accepted Answer · 2010-03-17 18:25:52Z

3

 for index, group in enumerate(FundTypeGroups):
     print "%s: %s" % (index, group)

(and the variables should not start with a capital letter...)

answered Mar 17, 2010 at 18:25

kennytm

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2 Comments

Count Boxer Over a year ago

If I change the string from "G02A" to something that doesn't match the pattern and no groups are returned, would I then add "except AttributeError" to catch this condition?

kennytm Over a year ago

@Count: Yes, or check if FundTypeGroups is None before looping.

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