python parse and print text before .(dot)

Question

I am trying a program where it has to parse the text file:qwer.txt and print the value before '=' and after ',':

qwer.txt

john.xavier=s/o john
jane.victory=s/o ram

output:

 xavier
 victory

My program shows the entire line,please help on how to display specific text after . and =

with open("qwer.txt", 'r') as my_file:
     a = my_file.readlines()
     for line in a:
        for part in line.split():
             if "=" in part:
                print part.split(' ')[-1]

Please help! answers will be appreciated.

It would help if you were actually splitting the string on a character in for part in line.split() (4th line in your example) — RevanProdigalKnight
– RevanProdigalKnight, Commented Jul 11, 2014 at 13:55
I expect you should probably have a .split(".") somewhere... — Kevin
– Kevin, Commented Jul 11, 2014 at 13:57

Vasily Ryabov · Accepted Answer · 2014-07-11 13:57:21Z

4

with open("qwer.txt", 'r') as my_file:
    for line in my_file:
        print line.split('=')[0].split('.')[1]

answered Jul 11, 2014 at 13:57

Vasily Ryabov

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3 Comments

adarshram Over a year ago

i get output but also error as : print line.split('=')[0].split('.')[1] IndexError: list index out of range >>>

thiruvenkadam Over a year ago

@adarshram It might be because there might not be a '.' in the name mentioned.

Vasily Ryabov Over a year ago

OK, you can add if ('=' in line) and ('.' in line): to check the string is applied for expected condition.

thiruvenkadam · Accepted Answer · 2014-07-11 14:01:30Z

0

You might need to understand the with statement better :-)

Here is my solution:

with open("qwer.txt", 'r') as my_file:
for line in my_file:
    name = line.split("=", 1)[0]
    print name.split(".")[-1]

The two lines can be combines like this as well:

print line.split("=", 1)[0].split(".")[-1]

The official doc of "with" statement is here

answered Jul 11, 2014 at 14:01

thiruvenkadam

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Comments

MikeRixWolfe · Accepted Answer · 2014-07-11 14:31:41Z

0

Fun little way using regex rather than splitting, and will ignore bad lines rather than erroring (pretty slick if I do say so myself). Also gives you a nice list of names if you want to use them further rather than outputting.

import re

r = re.compile('.+?\.(.+)?\=.+')

with open("qwer.txt", 'r') as f:
    names = [r.match(x).group(1) for x in f.read().splitlines() if r.match(x)]

for name in names: print name

edited Jul 11, 2014 at 14:31

answered Jul 11, 2014 at 14:18

MikeRixWolfe

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