Ajax Call With CodeIgniter Using Post

Question

I am using a simple POST to one of my controllers using Ajax, however in my in development tools it seems to never be able to find the controller. I get the error

POST http:// localhost:8888/time.php/checkit 404 (Not Found)

I'm not sure if this has something to do with the routes of CodeIgniter or the .htaccess file.

My Ajax call looks like:

  $("#submittodo").click(function () {
      $.ajax({
          url: 'time.php/checkit',
          type: "POST",
          data: {name: $(this).val()},
          success: function (data) {
           alert(data);
          }
      });
  });

can you visit http:// localhost:8888/time.php/checkit in your browser? for code igniter that looks like a really strange url. are you trying to hit /time/checkit ? could you elaborate on whats going wrong here? not much to go on. — Rooster
– Rooster, Commented Jul 11, 2014 at 19:51

Aarranz · Accepted Answer · 2014-07-12 09:37:25Z

1

Yo need to include base_url() on your url:

$("#submittodo").click(function () {
  $.ajax({
      url: '<?php echo base_url()?>time.php/checkit',
      type: "POST",
      data: {name: $(this).val()},
      success: function (data) {
       alert(data);
      }
  });
});

Also, check your config file, if you have $config['csrf_protection'] set to TRUE, you also need to get csrf token like this:

var post_data = {
    'name': $(this).val(),
    '<?php echo $this->security->get_csrf_token_name(); ?>' : '<?php echo $this->security->get_csrf_hash(); ?>'
};

$("#submittodo").click(function () {
  $.ajax({
      url: '<?php echo base_url()?>time.php/checkit',
      type: "POST",
      data: post_data,
      success: function (data) {
       alert(data);
      }
  });
});

answered Jul 12, 2014 at 9:37

Aarranz

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Comments

Nil'z · Accepted Answer · 2014-07-12 07:43:18Z

0

If you are using CI, you need to follow the URL structure, e.g: domain. com/controller/method.c In your case:

URL : '<?Php echo base_url( ) ?>time/checkit',

Mind that there isn't no .Php appended to the controller name. And an absolute URL is used.

answered Jul 12, 2014 at 7:43

Nil'z

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Comments

Dexter · Accepted Answer · 2014-07-12 09:37:01Z

0

try like this

 $("#submittodo").click(function () {
      $.ajax({
          url: '<?Php echo base_url(); ?>time/checkit',
          type: "POST",
          data: {name: $(this).val()},
          success: function (data) {
           alert(data);
          }
      });
  });

answered Jul 12, 2014 at 9:37

Dexter

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