How to write a url request along with parameters so it returns string?

Question

I have a url , and two parameters to pass before making request. What I am doing is appending values of all the url, parameterA, and parameterB.

NSString*urlString=@"www.example.com";
NSString*paramA=@"day=20140715";
NSString*paramA=@"mode=2ndMode";
   NSArray *URLArray = [[NSArray alloc] initWithObjects:urlString,paramA,paramB, nil];
        NSString *helloString = [URLArray componentsJoinedByString:@""];
 NSData *dataA = [NSData dataWithContentsOfURL:helloString];
 NSString *responseSt = [[NSString alloc] initWithData:dataA encoding:NSUTF8StringEncoding];

NOW THIS IS EASY WAY DOING A CONNECTION, BUT HOW DO WE WRITE A METHOD FOR URL REQUEST IN A PROPER WAY? Something that returns string after the request is complete.

-(void)url(NSString*)helloString ParameterA(NSString*)paramA ParameterB(NSString*)paramB ??

You will get response object from your server, if you want to return a string then return a string from server, it totally depends on you what you want to return after calling a request to server. — Yogesh Suthar
– Yogesh Suthar, Commented Jul 15, 2014 at 12:12
I want to write a request for example -(void)url(NSString*)helloString ParameterA(NSString*)paramA ParameterB(NSString*)paramB — Neprocker
– Neprocker, Commented Jul 15, 2014 at 12:15

Pradip Vanparia · Accepted Answer · 2014-07-15 12:20:49Z

2

NSString*url = @"www.example.com";
NSString*paramA = @"day=20140715";
NSString*paramB = @"mode=2ndMode";
NSArray *params = [[NSArray alloc] initWithObjects:paramA,paramB, nil];
NSString *URLStr = [params componentsJoinedByString:@"&"];
URLStr = [url stringByAppendingFormat:@"?%@",URLStr];
NSData *dataA = [NSData dataWithContentsOfURL:[NSURL URLWithString:URLStr]];
NSString *responseSt = [[NSString alloc] initWithData:dataA encoding:NSUTF8StringEncoding];

Try this code.

answered Jul 15, 2014 at 12:20

Pradip Vanparia

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