require function parameter to implement multiple interfaces

Question

In typescript, is it possible to do something of the sort:

module module1 {
    export interface Foo {
        data1: string;
    }
    export interface Bar {
        data2: string;
    }
    export function foobar(data: Foo & Bar) {
        //do stuff
        data.data1; data.data2;
    }
}

Namely, force foobar's data parameter to implement both Foo and Bar? And if so, what is the correct syntax?

Thanks.

Ryan Cavanaugh · Accepted Answer · 2014-07-15 19:56:31Z

7

You'd have to make a new named interface:

module module1 {
    export interface Foo {
        data1: string;
    }
    export interface Bar {
        data2: string;
    }
    export interface FooAndBar extends Foo, Bar { }
    export function foobar(data: FooAndBar) {
        //do stuff
        data.data1; data.data2;
    }
}

answered Jul 15, 2014 at 19:56

Ryan Cavanaugh

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