Python: turtle - (exit)onclick while in infinite loop?

Question

I am learning Python (2.7) and currently turtles is on the list.

Regards the documentation there are exitonclick() and onclick() etc. functions. However, I have some problems utilizing them.

For instance: This click event is working, but only after the loop finishes:

[...]
for i in range(4):
    trtl.forward(100)
    trtl.left(90)
scrn.exitonclick()
[...]

But what I'd like to do are things like this (but are not working):

[...]
while not scrn.screenonclick():
    trtl.forward(100)
    trtl.left(91)
[...]

or maybe like this:

[...]
while True:
    trtl.forward(100)
    trtl.left(91)
    scrn.screenonclick(break)
[...]

I think you get the general idea about what concepts I try to experiment with.

Any tips in using these onclick methods or any alternative ways in accomplishing an onclick interrupt?

Thanks!

arocks · Accepted Answer · 2014-07-17 13:18:02Z

1

Have you tried moving the click handler to the beginning? Here binding to the click will be made before the drawing starts:

def say_bye(x, y):
    bye()

scrn.onclick(say_bye)

for i in range(4):
    trtl.forward(100)
    trtl.left(90)

edited Jul 17, 2014 at 13:18

answered Jul 17, 2014 at 10:51

arocks

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6 Comments

Vankog Over a year ago

hm, unfortunately it is not an attribute: "AttributeError: '_Screen' object has no attribute 'screenonclick'"

Vankog Over a year ago

Unfortunately, the second idea does not work neither. The program just blocks on exitonclick() until the screen is clicked - which obviously exits the screen before it goes into the loop. ^^

arocks Over a year ago

One more try please :)

Vankog Over a year ago

Thx for your persistence. :-) Yes this works! At least in a pragmatic way. The downside seems to be that the Screen instance has to be a global variable, so bye() can be called. :-/

arocks Over a year ago

Wonderful! Could you accept the answer if you are happy with it? Here is how: meta.stackexchange.com/questions/23138/…

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