java String query

Question

i have a requirement i needed to be figure out .

consider a string for ex "/XXXXXXXXX/XXXXXXXXX/XXXXXXXXX/XXXXXXX ......n times "

I needed to get the second set of string from this string,last string set,with out last string set rest of the String. xx mentioned in example can be a-z,A-z,0-9,and spaces also. i am able to get last string set,with out last string set rest of the String. please let me know how to get 2nd string set.

              String a ="/WorkGroups/Testing Test WG 1/R14A";
              int position = a.lastIndexOf('/');
              System.out.println(position);//Print 28 
              System.out.println(a.substring(0,position));//print /WorkGroups/EriDoc Test WG 1
              System.out.println(a.substring(position+1));//print R14A

how to get only Testing Test WG 1 ?

a little bit more clarification please

nobalG
– nobalG

2014-07-17 11:22:03 +00:00
Commented Jul 17, 2014 at 11:22 — nobalG
– nobalG, Commented Jul 17, 2014 at 11:22

TheLostMind · Accepted Answer · 2014-07-17 11:22:13Z

1

String[] arr = yourString.split("/");
arr[whateverIndexYouWant]

answered Jul 17, 2014 at 11:22

TheLostMind

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Ninad Pingale · Accepted Answer · 2014-07-17 11:22:53Z

0

Here is the code -

    String a ="/WorkGroups/Testing Test WG 1/R14A";
    System.out.println(a.split("/")[2]);

Output -

 Testing Test WG 1

answered Jul 17, 2014 at 11:22

Ninad Pingale

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Comments

Spartan01 · Accepted Answer · 2014-07-17 11:25:31Z

0

This is an option :

System.out.println(a.substring(12, 28)

First parameter is an index of a start element, second parameter is an index of last element.

answered Jul 17, 2014 at 11:25

Spartan01

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