How to find recurring patterns in regex

Question

I'm trying to find a regex pattern from list of strings. Specifically trying to return the ports.

data = '''348  VLAN0348                         active    Fa4/24, Fa4/26, Gi2/4
349  VLAN0349                         active    Fa6/40, Fa6/43, Fa6/45
350  VLAN0350                         active    Fa6/41, Gi3/40'''.split('\n')

Using this code I've been able sift out the first string, but I need the rest.

FoundPorts = []
if checkVlan in x:
        port = re.search(r'active    (\S*)',x)
            if port != None:
                FoundPorts.append(port.group(1))`

Ideally I'd get:

FoundPorts = ['Fa4/24','Fa4/26','Gi2/4','Fa6/40','Fa6/43','Fa6/45','Fa6/41','Gi3/40']

Casimir et Hippolyte · Accepted Answer · 2014-07-21 17:28:50Z

1

You can use the new regex module:

import regex

data = '''348  VLAN0348                         active    Fa4/24, Fa4/26, Gi2/4
349  VLAN0349                         active    Fa6/40, Fa6/43, Fa6/45
350  VLAN0350                         active    Fa6/41, Gi3/40'''

print regex.findall(r'(?:\G(?!^),\s*|\bactive)\s+([^\s,]+)', data)

answered Jul 21, 2014 at 17:28

Casimir et Hippolyte

90k5 gold badges102 silver badges131 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Cory Kramer · Accepted Answer · 2014-07-21 17:16:34Z

0

This isn't using a regex, but it should do the trick

data = '''348  VLAN0348                         active    Fa4/24, Fa4/26, Gi2/4
349  VLAN0349                         active    Fa6/40, Fa6/43, Fa6/45
350  VLAN0350                         active    Fa6/41, Gi3/40'''

[i.strip(",") for i in data.split() if "/" in i]

Output

['Fa4/24', 'Fa4/26', 'Gi2/4', 'Fa6/40', 'Fa6/43', 'Fa6/45', 'Fa6/41', 'Gi3/40']

answered Jul 21, 2014 at 17:16

Cory Kramer

119k19 gold badges176 silver badges233 bronze badges

Comments

Abhijit · Accepted Answer · 2014-07-21 17:18:05Z

0

If you want to do with the regex path, the following regex pattern would do the trick

>>> re.findall(r"[A-Z][a-z]\d/\d\d?", data)
['Fa4/24', 'Fa4/26', 'Gi2/4', 'Fa6/40', 'Fa6/43', 'Fa6/45', 'Fa6/41', 'Gi3/40']

Another alternative to regex, that will work with your sample data is to use fnmatch

>>> import fnmatch
>>> [elem.rstrip(',') for elem in fnmatch.filter(data.split(),"*/*")]
['Fa4/24', 'Fa4/26', 'Gi2/4', 'Fa6/40', 'Fa6/43', 'Fa6/45', 'Fa6/41', 'Gi3/40']

answered Jul 21, 2014 at 17:18

Abhijit

64k20 gold badges143 silver badges209 bronze badges

Comments

Avinash Raj · Accepted Answer · 2014-07-21 17:35:55Z

0

Through regex module,

>>> import regex
>>> data = '''348  VLAN0348                         active    Fa4/24, Fa4/26, Gi2/4
... 349  VLAN0349                         active    Fa6/40, Fa6/43, Fa6/45
... 350  VLAN0350                         active    Fa6/41, Gi3/40'''
>>> m = regex.findall(r'(?<=active\s*)[\w/]+|(?<=,\s*)[\w/]+', data)
>>> m
['Fa4/24', 'Fa4/26', 'Gi2/4', 'Fa6/40', 'Fa6/43', 'Fa6/45', 'Fa6/41', 'Gi3/40']

answered Jul 21, 2014 at 17:35

Avinash Raj

175k32 gold badges247 silver badges289 bronze badges

Comments

Mark Wei · Accepted Answer · 2014-07-21 18:06:42Z

0

I think i got the answer by sifting for "/".

for x in d:
    s = re.findall(r'(\S*/\S*)',x)
    if s != None:
        print s
        if len(s) > 1:
            FoundPorts .extend(s)
        elif len(s) == 1:
            FoundPorts .extend(s)

Not as complex as most of the answers and thank you for them! I'll take a closer look at the Regex module.

answered Jul 21, 2014 at 18:06

Mark Wei

1013 bronze badges

Collectives™ on Stack Overflow

How to find recurring patterns in regex

5 Answers 5

Comments

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

5 Answers 5

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related