Error in For Loop - Swift Language

Question

I am copying this very simple line of code from Apple's swift tutorial, but it generates the following error:

.. is unavailable: half open range operator .. has been renamed to ..< (strangely, .. is NOT renamed to ..<)

var firstForLoop = 0
for i in 0..3 {
    firstForLoop += i
}

I have tried adding "var":

for var i in 0..3 {
    firstForLoop += i
}

And somewhat counterintuitively, that results in "i" being unidentified! I would expect i to be unidentified in the first loop, not the second.

Well, this is pretty obvious, replace 0..3 in your code with 0..<3. Apple renamed the operator — Zedenem
– Zedenem, Commented Jul 24, 2014 at 9:17
you should use ..< instead of .., and i don't understand your question. — lighter
– lighter, Commented Jul 24, 2014 at 9:17
You can download a current version of the Swift book, it has already been updated for the beta 4 release. The change is also documented in the beta 4 release notes. — Martin R
– Martin R, Commented Jul 24, 2014 at 9:37
I didn't know how to interpret the error message. It mentions that .. is replaced. I didn't realize that means that the operator is actually replaced in the swift language! — Kokodoko
– Kokodoko, Commented Jul 24, 2014 at 9:56

GoZoner · Accepted Answer · 2017-01-03 15:24:33Z

7

You are using older knowledge/documentation/code with a newer release of the Swift language. The half-closed range operator changed to ..< with the closed range operator remaining as .... Thus use:

for i in 0..<3 { /* ... */ }

In action:

> for i in 0..<3 { print (i) }
0
1
2

edited Jan 3, 2017 at 15:24

answered Jul 24, 2014 at 14:38

GoZoner

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