Getting function scope variable value after declaring a global variable with the same name

Question

so imagine I have this PHP code

<?php
    $var = 10;

    function foo($var)
    {
        global $var;
        echo $var;
    }

    foo(2);
?>

The output here is 10. I want to know if there is a way to refer back to the function scope variable $var (which in my example has a value of 2).

No. Once you declare a variable global within a function, any previous "local" version of that variable name is gone. You'd have to store the param in some OTHER variable. — Marc B
– Marc B, Commented Jul 24, 2014 at 14:40
Can you not name the function parameter something other than the global variable name? — crush
– crush, Commented Jul 24, 2014 at 14:41
@crush indeed I can, but then I don't have a question for SO now do I :). — Denis Kralj
– Denis Kralj, Commented Jul 24, 2014 at 14:55

AbraCadaver · Accepted Answer · 2014-07-24 15:20:47Z

1

Maybe not an exact answer but here is a way:

$var = 10;

function foo($var)
{
    $array = get_defined_vars();
    global $var;
    echo $var;
    echo $array['var'];
}

foo(2);

You could also use func_get_arg() or func_get_args(), but whatever you do would need to be before the global statement.

edited Jul 24, 2014 at 15:20

answered Jul 24, 2014 at 15:15

AbraCadaver

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2 Comments

Denis Kralj Over a year ago

Yea, i thought that this might be the only way, but wanted to check if there's perhaps a keyword of some sort that drives the declaration back to function scope.

AbraCadaver Over a year ago

And actually this would be the same as $foo = $var; and then accessing $foo later.

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