How to display error when there is nothing to fech from DB in PHP

Question

below is a code to display table rows fetched from DB when the Sql Query returnes result.

<?php
if(isset(['submit']))
{
$key=$_POST['txt_srchKey'];
}



if($key!="")
{
$all_entries=mysql_query("SELECT * FROM tbl_book WHERE bookAuthor='$key'|| bookName='$key'||bookCode='$key' "); 
?>  
<table border=1 align="left">
<tr>
<td><b>Book Code</b></td><td><b>Book Name</b></td><td><b>Edition</b></td><td><b>Author</b></td>
</tr>
<?php
while($row=mysql_fetch_array($all_entries))
{ ?>

<tr>
<td><?php echo $row['bookCode'] ?></td>
<td><?php echo $row['bookName'] ?></td>

<td><?php echo $row['bookEdition'] ?></td>
<td><?php echo $row['bookAuthor'] ?></td>
</tr>
<?php
}   
?>              
</table>

I am getting the result in the table when the condition (bookAuthor='$key'|| bookName='$key'||bookCode='$key')is true.but if there is no result it only showing the table headins eg:Book Code, Book Name etc. But instead of this I need to display 'No result found'.How can I do this by editing my code?

Firstly, this if(isset(['submit'])) is invalid. It should read as if(isset($_POST['submit'])) — Funk Forty Niner
– Funk Forty Niner, Commented Jul 26, 2014 at 4:41

Alexander O'Mara · Accepted Answer · 2014-07-26 05:00:59Z

Without immediately getting into the problems with your code, you can use mysql_num_rows.

<?php
if(isset(['submit']))
{
    $key=$_POST['txt_srchKey'];
}
if($key!="")
{
    $all_entries=mysql_query("SELECT * FROM tbl_book WHERE bookAuthor='$key'|| bookName='$key'||bookCode='$key' "); 
    if(mysql_num_rows($all_entries) > 0)
    {
        ?>  
        <table border=1 align="left">
        <tr>
            <td><b>Book Code</b></td><td><b>Book Name</b></td><td><b>Edition</b></td><td><b>Author</b></td>
        </tr>
        <?php
        while($row=mysql_fetch_array($all_entries))
        {
        ?>
            <tr>
                <td><?php echo $row['bookCode'] ?></td>
                <td><?php echo $row['bookName'] ?></td>
                <td><?php echo $row['bookEdition'] ?></td>
                <td><?php echo $row['bookAuthor'] ?></td>
            </tr>
        <?php
        }   
        ?>              
        </table>
        <?php
    }
    else
    {
        ?><p>No result found</p><?php
    }
}

There are a few things about this code that I should draw attention to:

Issue 1

This line is invalid:

if(isset(['submit']))

I think you mean to use:

if(isset($_POST['submit']))

Issue 2

This SQL statement is wide-open to SQL injection:

mysql_query("SELECT * FROM tbl_book WHERE bookAuthor='$key'|| bookName='$key'||bookCode='$key' ")

You could improve security on this by using mysql_real_escape_string when you set $key like this:

$key=mysql_real_escape_string($_POST['txt_srchKey']);

However, this is not a perfect solution in all cases, when brings me to my final point.

Issue 3

mysql_query and all the other mysql_* are deprecated in the latest versions of PHP. See the warning on the mysql_query page and the MySQL: choosing an API for more information. You may want to consider using MySQLi or PDO as making secure database queries is much easier in these extensions.

Khushboo · Accepted Answer · 2014-07-26 04:43:35Z

0

Try below :-

if(mysql_num_rows($all_entries) > 0){
<table border=1 align="left">
<tr>
<td><b>Book Code</b></td><td><b>Book Name</b></td><td><b>Edition</b></td><td><b>Author</b></td>
</tr>
<?php
while($row=mysql_fetch_array($all_entries))
{ ?>

<tr>
<td><?php echo $row['bookCode'] ?></td>
<td><?php echo $row['bookName'] ?></td>

<td><?php echo $row['bookEdition'] ?></td>
<td><?php echo $row['bookAuthor'] ?></td>
</tr>
<?php
}   
?>              
</table>
<?php } ?>

answered Jul 26, 2014 at 4:43

Khushboo

1,8191 gold badge11 silver badges17 bronze badges

Comments

K.Raj. · Accepted Answer · 2014-07-26 04:53:15Z

0

Before using mysql_fetch_array function always check records are coming from database or not

Using mysql_num_rows function

Example : if(mysql_num_rows($all_countries) > 0)

Add this code after your </table> tag

<?php   
      }   
       else  
       {         
          echo  "No Record Found";   
       }  
 ?>

if possible then use !empty instead of isset in your code

answered Jul 26, 2014 at 4:53

K.Raj.

6536 silver badges22 bronze badges

Comments

Patrick D'appollonio · Accepted Answer · 2014-07-26 05:00:37Z

0

Prepend a condition before the while like this:

<?php 
    $number_of_results = mysql_num_rows($all_entries); 
    if ($number_of_results > 0) {
        while($row=mysql_fetch_array($all_entries)) { 
?>
<tr>
<td><?php echo $row['bookCode'] ?></td>
<td><?php echo $row['bookName'] ?></td>
<td><?php echo $row['bookEdition'] ?></td>
<td><?php echo $row['bookAuthor'] ?></td>
</tr>
<?php 
        } 
    } else {
?>   
<tr>
<td colspan="4">No results found</td>
</tr>
<?php
    }
?>

Please, be advised that the functions you're using right now are deprecated. They're also a common source for SQL injections and websites getting hacked. You could use something more adequate by using PDO or MySQLi.

edited Jul 26, 2014 at 5:00

answered Jul 26, 2014 at 4:48

Patrick D'appollonio

2,7821 gold badge20 silver badges34 bronze badges

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